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masya89 [10]
3 years ago
13

Y=2x+8 and y= -2/3x. Identify the value of x that simultaneously satisfies both equations.

Mathematics
1 answer:
son4ous [18]3 years ago
5 0
Let's solve this by subst. (-2/3)x for y in y=2x+8.

Then 2x+8 = (-2/3)x.  (For clarity you must use those parentheses.)

The LCD is 3.  Mult. both sides by 3, obtaining

6x+24 = -2x.  Then 8x = -24, and x = -3.  Now that you have a value for x, subst. this value (-3) into either of the given equations to determine y.

Then write your solution in the form (-3,  ??  ).
You might be interested in
In triangle PQR, PR = 23mm, QR = 39mm, and m<R = 163 degrees. Find the area of the triangle to the nearest tenth.
Schach [20]

Answer: 131.1287 square mm (approx)

Step-by-step explanation:

The area of a triangle,

A=\frac{1}{2} \times s_1\times s_2\times sin \theta

Where s_1 and s_2 are adjacent sides and \theta is the include angle of these sides,

Here PR and QR are adjacent sides and ∠R is the included angle of these sides,

Thus, we can write,

s_1 = PR= 23\text{ mm}, s_2=QR=39\text{ mm} and \theta = 163^{\circ},

Thus, the area of the triangle PQR,

A=\frac{1}{2} \times 23\times 39\times sin163^{\circ}

A=\frac{262.257419136}{2} = 131.128709568\approx 131.1287\text{ square mm}

5 0
3 years ago
Which solution set is graft on the number line
vfiekz [6]

Answer:

x < 1

Step-by-step explanation:

an open circle means it contains no equal signs.....everything to the left is shaded....means it is less then

x <  1 (thats a less then sign only) ....no equal sign in there

4 0
2 years ago
Read 2 more answers
Answers ASAP plsssssss
ASHA 777 [7]

Answer:

Step-by-step explanation:the answer is option A as 1 • 3 =3 and 3+4=7

6 0
3 years ago
Kevin and Randi have a jar containing 63 coins , being either quarters or nickels . they total
Softa [21]
Yess, such fun so

q=number of quarter
n=number of nickles
q+n=63

9.15=915 cents
25 cents=1 q
5 cents=1 n so

915=25q+5n
915=5(5q+n)
divide by 5
183=5q+n

we also have q+n=63
subtract q from both sides
n=63-q
subsitute 63-q for n in second equation
183=5q+63-q
add like terms
183=4q+63
subtract 63 from both sides
120=4q
divdie by 4
30=q
there were 30 quarters
subsitute
63=30+n
subtract 30
33=n


30 quarters
33 nicles

8 0
3 years ago
I need help please this is confusing
kap26 [50]

Step-by-step explanation:

slope formula when it's perpendicular : m1 × m = -1

Now Differentiate the quadratic function given.

d/dx ( x^2 - x + 1 ) at an x value of -1 from the point "(-1 , 3 )"

= 2x - 1 .... plug in the x value

= 2 × -1 - 1 = -3.

Use this equation...

y - y1 = m(x - x1)

m = slope = derivative at x = -1

y1 = value found by subbing -1 into the original function

x1 = the x value often given.

y - 3 = 1/3 (x + 1)

= 1/3x + 1/3 + 3

y = 1/3x + 10/3.

not sure about this one - it probably intersects at the x & y intercepts of the equation of the normal line.

y = 0 + 10/3 = 10/3

1/3x = 0 - 10/3

x = -10/3 / 1/3 = -10

so the point .... (-10 , 10/3)

7 0
2 years ago
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