Question

Company ABC has one thermostat, two boilers, and one water gauge. For a company to be properly heated, the thermostat and a minimum of one boiler must be operational (both boilers can also be operational). The water gauge is not a factor. History shows that each boiler is operational 72% of the time. The thermostat is operational 94% of the time and the water gauge is operational 87% of the time. Failures of either the thermostat, boilers or water gauge are independent of each other. What is the probability that company ABC is properly heated.

Answer 1

Answer: 0.866304

Step-by-step explanation:

Let A be the event that thermostat is operational and B shows the event that at least one boiler is operational.

The probability that thermostat is operational is  P(A) = 0.94

The probability that both boiler is not operational is $(1 - 0.72)\times(1-0.72) = 0.0784$

The probability that at least one boiler is operational is

$P(B) = 1 - 0.0784 = 0.9216$   [ Using complement rule]

But water gauge is not a factor, thus the probability that company ABC is properly heated is

$P(T) \times P(B) = 0.94 \times0.9216 = 0.866304$

Hence, the probability that company ABC is properly heated. = 0.866304