The length of a rectangle 8 more than the width .the area is 513 square inches .find the length and width of the rectangle
1 answer:
Answer:
width =19 inches
length= 27 inches
Step-by-step explanation:
Let width be w inches so according to given scenario as length is 8 more than width so the equation becomes
l=8+w inches (Equation 1)
Area of Rectangle= L*w
Area= 513
L*w=513 (Equation 2)
Putting l's value from equation 1 in equation 2
(8+w)w=513
w^2+8w-513=0
Making Factors
w^2+27w-19w-513=0
w(w+27)-19(w+27)=0
(w-19)(w+27)=0
w=19, w=-27
as width cannot be negative so if we only consider w=19 then
l=8+19
l=27
You might be interested in
Answer:
Step-by-step explanation:
fog(x)=f(g(x))
so it comes
<u>so C is the correct answer</u>
Answer:
your answer is correct
Step-by-step explanation:
-5 x -4=20
20+3=23
I’m not sure the answer but go into a webpage called Desmos and it will show you
Answer:
The concep of rectilinean line between point A and point B.
Search about euclidean laws.
Besr regards
