The length of a rectangle 8 more than the width .the area is 513 square inches .find the length and width of the rectangle

Mathematics

1 answer:

Pani-rosa [81]3 years ago

3 0

Answer:

width =19 inches

length= 27 inches

Step-by-step explanation:

Let width be w inches so according to given scenario as length is 8 more than width so the equation becomes

l=8+w inches (Equation 1)

Area of Rectangle= L*w

Area= 513

L*w=513 (Equation 2)

Putting l's value from equation 1 in equation 2

(8+w)w=513

w^2+8w-513=0

Making Factors

w^2+27w-19w-513=0

w(w+27)-19(w+27)=0

(w-19)(w+27)=0

w=19, w=-27

as width cannot be negative so if we only consider w=19 then

l=8+19

l=27

You might be interested in

In the Granger cases of the 1870s involving railroad regulation, Supreme Court decisions were significant because the decisions

Llana [10]

In the Granger cases of the 1870s involving railroad regulation, Supreme Court decisions were significant because the decisions established that

2. government can regulate private business in the public interest

In response to the Supreme Court's 1886 ruling with regards to the Granger cases, Congress passed the Interstate Commerce Act of 1887. This act allowed federal regulations to be implemented on interstate lines.

3 0

3 years ago

Solve 4(2x-3)=6x+2 I don't understand the steps pls

Marysya12 [62]

Answer: x = 7

Step-by-step explanation:

4(2x-3) = 6x+2 <--distribute the 4

8x - 12 = 6x + 2 <---add 12 to both sides

8x = 6x + 14 <--- subrtract 6x from both sides

2x = 14 <--- divide by two

x = 7

6 0