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storchak [24]
4 years ago
5

Which relation represents a function? A. {(0, 3), (2, 4), (0, 6)} B. {(-7, 5), (-7, 1), (-10, 3), (-4, 3)} C. {(2, 0), (6, 2), (

6, -2)} D. {(-6, 5), (-3, 2), (1, 2), (6, 5)}
Mathematics
1 answer:
xz_007 [3.2K]4 years ago
5 0
If there are two of the same x values in a set, it is not a function. Therefore, the answer is D. Hope this helps, and please mark brainliest!
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The credit remaining on a phone card (in dollars) is a linear function of the total calling time made with the card (in minutes)
saw5 [17]

Answer: $19.6

Step-by-step explanation:

Linear function: f(x)=mx+c

, where  m= rate of change in f(x) with respect to x.

c = Initial value.

Let c = Initial value of card , m= Charge per minute

x= Number of minutes calling time.

Then, 25.06= 38m+c   (i)

21.03=69m+c (ii)

Eliminate (ii) from (i)

4.03=-31m\\\\\Rightarrow\ m=\dfrac{4.03}{-31}\\\\\Rightarrow\ m=-0.13

Put m in (i) , we get

25.06= 38(-0.13)+c\\\\\Rightarrow\ 25.06=-4.94+c\\\\\Rightarrow\ c=25.06+4.94\\\\\Rightarrow\ c=30

i.e. f(x)=-0.13x+30

if x=80 then

f(80)= -0.13(80)+30

=-10.4+30

=19.6

Hence, the remaining credit after 80 minutes of calls = $19.6

7 0
3 years ago
Find the conjugate and product of<br><br>2-i5 ​
WITCHER [35]

Answer: 2+i5,\ 29

Step-by-step explanation:

Given

Complex number is 2-i5

Its conjugate is obtained by changing the sign of the original number i.e. 2+i5

The product of the two numbers is

\Rightarrow (2-i5)(2+i5)=2^2-(5i)^2\quad \quad [(x+y)(x-y)=x^2-y^2]\\\\\Rightarrow (2-i5)(2+i5)=4-25i^2\\\\\Rightarrow (2-i5)(2+i5)=4+25=29

3 0
3 years ago
Give the prime factorization of the number. use exponents when possible <br> 126
nataly862011 [7]

Answer:

=2*3^2 *7

Step-by-step explanation:

Prime factorization means to simplify 126 down to prime numbers

126 = 2*63

     = 2* 9*7

     = 2*3*3*7

Since 2 3 and 7 are prime numbers, we rewrite these with exponents

     =2*3^2 *7

3 0
3 years ago
Please help me please hurry
Naya [18.7K]

Answer

899

Step-by-step explanation:

99

8 0
3 years ago
There were 45 runners to start a race. In the first half of the race, 1/3 of them dropped out. In the second half of the race, 3
Helen [10]
45/3=15 45-15=30 30/5=6 3x6=18 30-18=12 the answer is 12
5 0
3 years ago
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