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storchak [24]
3 years ago
5

Which relation represents a function? A. {(0, 3), (2, 4), (0, 6)} B. {(-7, 5), (-7, 1), (-10, 3), (-4, 3)} C. {(2, 0), (6, 2), (

6, -2)} D. {(-6, 5), (-3, 2), (1, 2), (6, 5)}
Mathematics
1 answer:
xz_007 [3.2K]3 years ago
5 0
If there are two of the same x values in a set, it is not a function. Therefore, the answer is D. Hope this helps, and please mark brainliest!
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Which data set is the most clustered around its mean?
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A because it is a pattern 4 6 4 8 and that is why it is a
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3 years ago
Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.
Alla [95]

Answer with explanation:

The given expression is:

 2 \sqrt{3}\cos x * \csc x+4 \cos x-3 \csc x-2\sqrt{3}\\\\=2 \cos x*(\sqrt{3}*\csc x+2)-\sqrt{3}*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)=0\\\\(2\cos x -\sqrt{3})=0 \wedge (\sqrt{3}*\csc x+2)=0

  \cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}

Option C

8 0
2 years ago
Bike rental company A charges an initial fee of $8 plus $1.25 for every hour spent biking. Bike rental company B charges $2.75 f
Lera25 [3.4K]
2.75h =8-1.25h is thus the one
7 0
3 years ago
We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

h'(t) = -32\cdot t +128

Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

-32\cdot t +128 = 0

t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

6 0
3 years ago
I really need this . Someone please help . Is it abc or d
prisoha [69]

Answer:

B

Step-by-step explanation:

lets start off by looking at point A (1,1)

4 units to the right is along the x-axis, so the x-coordinate would be 5 (1 + 4)

2 units up is on the y-axis, so the y-coordinate would be 3 (1 + 2)

A is now (5,3). we can eliminate choices A, C, and D as they each have negative numbers in them, and we are moving in the positive direction, not the negative.

the answer is B

7 0
3 years ago
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