1. The area of the photograph is:
A=LxW
A is the area of the photograph (A=54 in²).
L is the lenght of the photograph (L=12-4x).
W is the widht of the photograph (W=12-2x)
2. When you substitute these values into the formula A=LxW, you obtain:
A=LxW
54=(12-4x)(12-2x)
3. When you apply the distributive property, you have:
54=144-24x-48x+8x²
8x²-72x+144-54=0
4. Finally, you obtain a quadratic equation for the area of the photo:
8x²-72x+90=0
5. Therefore, the answer is:
8x²-72x+90=0
Answer:
44°
Step-by-step explanation:
The reference angle is the magnitude of the smallest angle between the terminal ray and the x-axis.
Your angle is one full circle clockwise plus 44° more (-360° -44° = -404°), so makes an angle of -44° with respect to the positive x-axis. The magnitude of that is 44°.
_____
<em>Using a function</em>
The attachment shows a calculator function that can be used to find the reference angle for any angle. (Replace the value -404 with the angle of your choice.)
Answer:
ΔDCE by ASA
Step-by-step explanation:
The marks on the diagram show AE ≅ DE. We know vertical angles AEB and DEC are congruent, and we know alternate interior angles BAE and CDE are congruent. The congruent angles we have identified are on either end of the congruent segment, so the ASA theorem applies.
Matching corresponding vertices, we can declare ΔABE ≅ ΔDCE.
Answer:
36
Step-by-step explanation:
473/13
= 36 .38
round to the lower whole number