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Nastasia [14]
3 years ago
13

7/8y +1/3 = 7/12 What does y equal?

Mathematics
2 answers:
Rasek [7]3 years ago
8 0
1 Simplify \frac{7}{8}y
​8
​
​7
​​ y to \frac{7y}{8}
​8
​
​7y
​​
\frac{7y}{8}+\frac{1}{3}=\frac{7}{12}
​8
​
​7y
​​ +
​3
​
​1
​​ =
​12
​
​7
​​

2 Subtract \frac{1}{3}
​3
​
​1
​​ from both sides
\frac{7y}{8}=\frac{7}{12}-\frac{1}{3}
​8
​
​7y
​​ =
​12
​
​7
​​ −
​3
​
​1
​​

3 Simplify \frac{7}{12}-\frac{1}{3}
​12
​
​7
​​ −
​3
​
​1
​​ to \frac{1}{4}
​4
​
​1
​​
\frac{7y}{8}=\frac{1}{4}
​8
​
​7y
​​ =
​4
​
​1
​​

4 Multiply both sides by 88
7y=\frac{1}{4}\times 87y=
​4
​
​1
​​ ×8

5 Simplify \frac{1}{4}\times 8
​4
​
​1
​​ ×8 to \frac{8}{4}
​4
​
​8
​​
7y=\frac{8}{4}7y=
​4
​
​8
​​

6 Simplify \frac{8}{4}
​4
​
​8
​​ to 22
7y=27y=2

7 Divide both sides by 77
y=\frac{2}{7}y=
​7
​
​2
​​
fiasKO [112]3 years ago
4 0
7/8y + 1/3 = 7/12

y = 2/7
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Answer:

vertex = (0, -4)

equation of the parabola:  y=3x^2-4

Step-by-step explanation:

Given:

  • y-intercept of parabola: -4
  • parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola:  y=a(x-h)^2+k

(where (h, k) is the vertex and a is some constant)

Substitute point (0, -4) into the equation:

\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}

Substitute point (-2, 8) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}

Substitute point (1, -1) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}

Equate to find h:

\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}

Substitute found value of h into one of the equations to find a:

\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}

Substitute found values of h and a to find k:

\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}

Therefore, the equation of the parabola in vertex form is:

\implies y=3(x-0)^2-4=3x^2-4

So the vertex of the parabola is (0, -4)

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