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3 years ago

9

If I get to watch my niece for 82 min. and then watch my little cuz for 67 min., how long do I watch both of them? Please includ

e hours and minutes.

2 answers:

lilavasa [31]3 years ago

6 0

Answer:

2.5 hours roughly (2 hours 29 mins)

Lady bird [3.3K]3 years ago

3 0

Answer:

1:49 is your answer. your welcome

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Verify by substitution whetherthe given functions are solutions of the given DE. Primes denote derivatives with respect to x.y!!

julia-pushkina [17]

Complete Question

The complete question is shown on the first uploaded

Answer:

$y_1$ is not a solution of the differential equation

$y_2$ is not a solution of the differential equation

$y_3$ is not a solution of the differential equation

Step-by-step explanation:

The differential equation given is $y'' + y' = cos2x$

Let consider the first equation to substitute

$y_1 = cosx +sinx$

$y_1' = -sinx +cosx$

$y_1'' = -cosx -sinx$

So

$y_1'' - y_1' = -cosx -sinx -sinx +cosx$

$y_1'' + y_1' = -2sinx$

So

$-2sinx \ne cos2x$

This means that $y_1$ is not a solution of the differential equation

Let consider the second equation to substitute

$y_2 = cos2x$

$y_2' = -2sin2x$

$y_2'' = -4cos2x$

So

$y_2'' + y_2' = -4cos2x-2sin2x$

So

$-4cos2x-2sin2x \ne cos2x$

This means that $y_2$ is not a solution of the differential equation

Let consider the third equation to substitute

$y_3 = sin 2x$

$y_3' = 2cos 2x$

$y_3'' = -4sin2x$

So

$y_3'' + y_3' = -4sin2x - 2cos2x$

So

$-4sin2x - 2cos2x \ne cos2x$

This means that $y_3$ is not a solution of the differential equation

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2 years ago

Confirm that (2x + 1)^2 + (2x^2 +2x)^2 = (2x^2 + 2x + 1)^2

Sergio [31]

Answer:

Step-by-step explanation:

(2x+1)^2+(2x^2+2x)^2=

(2x+1)^2=4x^2+4x+1

(2x^2+2x)^2=4x^4+8x^3+4x^2

4x^2+4x+1+4x^4+8x^3+4x^2=4x^4+8x^3+8x^2+4x+1

(2x^2+2x+1)^2=4x^4+8x^3+8x^2+4x+1

4x^4+8x^3+8x^2+4x+1=4x^4+8x^3+8x^2+4x+1

7 0

2 years ago