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4 years ago

Karina bought a pizza that was cut into 8 equal pieces. She ate half of one piece. What fraction of the whole pizza did she eat?

Mathematics

2 answers:

soldi70 [24.7K]4 years ago

6 0

The correct answer is 1/16

defon4 years ago

5 0

Answer: $\dfrac{1}{16}$

Step-by-step explanation:

Given : Karina bought a pizza that was cut into 8 equal pieces. She ate half of one piece.

Then , the fraction of each part of pizza = $\dfrac{1}{8}$

Also, She ate half of one piece.

Then the fraction of half of one piece will be :-

$\dfrac{1}{2}\times\dfrac{1}{8}=\dfrac{1}{16}$

Therefore, the fraction of the whole pizza she ate= $\dfrac{1}{16}$

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The coldest temperature ever recorded east of the Mississippi is fifty-four degrees below zero in Danbury, Wisconsin, on January

pav-90 [236]

Answer:

-54 degrees F

Step-by-step explanation:

The coldest temperature ever recorded east of the Mississippi is fifty-four degrees below zero in Danbury, Wisconsin, on January 24, 1922.

The temperature is below zero so it is negative,

-54 degrees F

3 0

3 years ago

Evaluate using integration by parts

PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

$I(n)=\displaystyle\int x^ne^x\,\mathrm dx$

One round of IBP, setting

$u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx$

$\mathrm dv=e^x\,\mathrm dx\implies v=e^x$

gives

$\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx$

$I(n)=x^ne^x-nI(n-1)$

This is called a power-reduction formula. We could try solving for $I(n)$ explicitly, but no need. $n=5$ is small enough to just expand $I(5)$ as much as we need to.

$I(5)=x^5e^x-5I(4)$

$I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)$

$I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)$

$I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)$

$I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))$

Finally,

$I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C$

so we end up with

$I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C$

$I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C$

and the antiderivative is

$\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C$

8 0

3 years ago

Jen pours out 6 ounces of water from a full bottle. She estimates that she poured out 20% of the water in the bottle. About how

faust18 [17]

Answer:

30 ounces i think

Step-by-step explanation:

20% times 5 = 100%

6 in every 20%

since there is 5 20%'s, multiply 6 times 5 and you get 30

7 0

3 years ago

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raketka [301]

I believe $11.4 not sure

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3 years ago

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maks197457 [2]

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6 0

3 years ago