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Nata [24]
3 years ago
14

42in to 9 feet insimplest form

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0
Dkjshsbdjsksmkakakakakkaka
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How to solve all of this
photoshop1234 [79]
Start circle: πd = (3.14)(19) = 59.7

Move diagonally to the circle with the radius of 6.2.

Second circle: 2πr = 2(3.14)(6.2) = 39

Move upwards to the circle with the radius of 10.5

third circle: 2πr = 2(3.14)(10.5) = 66

Move right to the circle with the diameter of 16.6

Fourth circle: πd = (3.14)(16.6) = 52.2

Move down to the circle with the diameter of 7.7

fifth circle: πd = (3.14)(7.7) = 24.2

Move down to the circle with the diameter of 50

Sixth circle: πd = (3.14)(50) = 157.1

Move left to the circle with the radius of 11.8

Seventh circle: 2πr = 2(3.14)(11.8) = 74.1

Move down to the circle with the radius of 38

Eight circle: 2πr = 2(3.14)(38) = 238.8

Move right to the circle with the diameter of 1.1

ninth circle: πd = (3.14)(1.1) = 3.5

Move right to the circle with the radius of 14.8

10th circle = 2πr = 2(3.14)(14.8) = 93

Move up to the end.

Hope this helps :) 
7 0
3 years ago
1
zmey [24]

Answer:

Part 1) The inequality that represent this situation is 5(x+7)^{2} \geq1,050  or  5x^{2}+70x+245 \geq1,050

Part 2) Yes, 8 inches is a reasonable width for his tablet

Step-by-step explanation:

Part 1)

Let

L -----> the length of the screen television

W ----> the width of the screen television

x ---->  the width of Andrew's tablet

we know that

L=5W ------> equation A

W=x+7 ----> equation B

The area of the television is

A=LW -----> equation C

Substitute equation A and equation B in equation C

A=5(x+7)(x+7)

A=5(x+7)^{2}

5(x+7)^{2} \geq1,050

5(x^{2}+14x+49) \geq1,050

5x^{2}+70x+245 \geq1,050 ------> inequality that represent this situation

Part 2) Determine if 8 inches is a reasonable width for his tablet

For x=8 in

Substitute in the inequality

5(8+7)^{2} \geq1,050

5(15)^{2} \geq1,050

1,125 \geq1,050 -----> is true

therefore

Yes, 8 inches is a reasonable width for his tablet

3 0
3 years ago
David had $35 to spend at the fair. If the admission to the fair is $4.5 and the rides cost $1.50 each, what is the greatest num
sleet_krkn [62]

Answer:

20 rides

Step-by-step explanation:

35-4.5=30.5

20*1.5=30 and 30 plus 4.5 equals 34.5

5 0
3 years ago
Plz help me with a and b <br>who can answer in a minute
Irina18 [472]
(a) \frac{1}{4}
(b) The Road Tennis Court occupies \frac{1}{3} of the shaded portion.

I hope it helps! ;)
5 0
4 years ago
Read 2 more answers
You have two cubes that you filled with water to make ice cubes. The first cube has a side length of 3 units. The second cube ha
Virty [35]
V = 3^3 = 5^3
Volume of each cube is side^3. To find the volume of both cubes just add the two volumes together.
5 0
3 years ago
Read 2 more answers
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