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malfutka [58]
3 years ago
9

In an all boys school, the heights of the student body are normally distributed with a mean of 71 inches and a standard deviatio

n of 5 inches. What percentage of the students are shorter than 76 inches tall, to the nearest tenth?
Mathematics
1 answer:
muminat3 years ago
7 0

Answer:

15.87%

Step-by-step explanation:

First thing here is that we calculate the z-score which corresponds to 76

mathematically;

z-score = (x-mean)/SD

mean = 71 and SD = 5

plugging these values, we have;

z = (76-71)/5 = 5/5 = 1

Now, we want to firstly get the probability that we have a student shorter than 76 inches

The probability we want to calculate is P(z<1)

we can get this using the z-score table directly

That would be 0.15866

In percentage that is 15.866% which is 15.87% to the nearest tenth

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The length of human pregnancies from conception to birth varies according to a distribution that is approximately normal with me
iragen [17]

Answer:

a) 229 and 305 days

b) 229 days or less

c) 305 days or more

Step-by-step explanation:

The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 267

Standard deviation = 19

(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days

By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.

So

267 - 2*19 = 229 days

to

267 + 2*19 = 305 days

(b) How short are the shortest 2.5% of all pregnancies?______days or less

95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So

267 - 2*19 = 229 days

c) How long do the longest 2.5% of pregnancies last?________days or more

Explanation in b)

267 + 2*19 = 305 days

7 0
3 years ago
Allison has 5 times as many baseball cards as football cards. In all she has 120 baseball and football cards. How many baseball
bekas [8.4K]
Allison has 600 baseball cards

3 0
3 years ago
What’s the measure of b?
barxatty [35]
It’s 79. Alternate exterior angles are equal.
5 0
3 years ago
Let SSS represent the number of sunflower plants and LLL represent the number of lily plants Ezra's water supply can water.
Fantom [35]

Answer:

Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.

Step-by-step explanation:

Given the inequality function

0.7S+0.5L≤11 where S represent the number of sunflower plants and L represent the number of lily plants Ezra's water supply can water, if Ezra waters 10 lily plants, then we can calculate the maximum amount of sunflower plant that he can water with the remaining amount of water by simply substituting L = 10 into the inequality function as shown;

0.7S+0.5L≤11

0.7S+0.5(10)≤11

0.7S+5≤11

Taking 5 to the other side:

0.7S≤11-5

0.7S≤6

S≤6/0.7

S≤8.57

This shows that Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.

3 0
3 years ago
Someone Please Help Me With This<br><br> n <br> _ = 1 6<br> 3
Ivahew [28]

Answer:

n=48

Step-by-step explanation:

n  

_ = 1 6

3

Multiply each side by 3

n/3 * 3 = 16*3

n = 48

3 0
3 years ago
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