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3 years ago

6

A new car depreciates at a rate of 15% per year. What is the expected value of a $25,000 car after 5 years (rounded to nearest w

hole dollar)?

1 answer:

Verdich [7]3 years ago

5 0

<span>V(t) = 25000*0.85^t
----
V(5) = 25000*0.85^5 = $11092.63
=$11093</span>

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For a sample of 35 items from a population for which the standard deviation is 20.5, the sample mean is 458. At the 0.05 level o

Anika [276]

Answer:

Value of test statistics = 2.30

Step-by-step explanation:

We are given that for a sample of 35 items from a population for which the standard deviation is 20.5, the sample mean is 458.

Also, Null Hypothesis, $H_0$ : $\mu$ = 450

Alternate Hypothesis, $H_1$ : $\mu\neq$ 450

The test statistics that will be used here is One sample t-test statistics;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 458

s = sample standard deviation = 20.5

n = sample of items = 35

So, test statistics = $\frac{458-450}{\frac{20.5}{\sqrt{35} } }$ ~ $t_3_4$

= 2.30

Therefore, the value of test statistics is 2.30 .

3 0

3 years ago

A circular region has a population of about 15,500 people and a population density of about 775 people per square kilometer. Fin

Reil [10]

Answer:

2.5 km

Step-by-step explanation:

First, find the area of the region:

A circular region has a population of about 15,500 people;
A population density of about 775 people per square kilometer.

So, there are $15,500 :775=20$ square kilometers.

Now, let x kilometers be the radius of the circular region, then

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To the nearest tenth this is 2.5 km.

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3 years ago