For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that
is such that

Obviously, both limits are 0, so
is indeed continuous at
.
Now, for
to be differentiable everywhere, its derivative
must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:

and at this time, we don't know what's going on at
, so we omit that case. We want
to be continuous, so we require that

from which it follows that
.
Point-slope form
y -24 = -4/5(x -0)
Find x when y is 0 (X-intercept)
0 -24 = -4/5(x -0)
-24 = -4/5x
x = -120/-4
x = 30
Answer: A. 30 minutes
The partial would be
40x5=200
2x5=10
210
Your just breaking them apart
Answer:
Numeric expressions apply operations to numbers. For example, 2(3 + 8) is a numeric expression. Algebraic expressions include at least one variable and at least one operation (addition, subtraction, multiplication, division). For example, 2(x + 8y) is an algebraic expression.
Step-by-step explanation: