Question

This is URGENT! PLEASE help me solve this question!

Answer 1

Answer:

x=0, x=2 or x=-2

Step-by-step explanation:

Hello, please consider the following.

$\dfrac{x^3-4x}{x^2+2x+1}=\dfrac{x(x^2-4)}{(x+1)^2}\\\\=\dfrac{x(x-2)(x+2)}{(x+1)^2}$

So to get this expression equal to zero it means x=0, x=2 or x=-2

The correct answer is the last one.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you