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Mamont248 [21]
3 years ago
6

This is URGENT! PLEASE help me solve this question!

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer:

x=0, x=2 or x=-2

Step-by-step explanation:

Hello, please consider the following.

\dfrac{x^3-4x}{x^2+2x+1}=\dfrac{x(x^2-4)}{(x+1)^2}\\\\=\dfrac{x(x-2)(x+2)}{(x+1)^2}

So to get this expression equal to zero it means x=0, x=2 or x=-2

The correct answer is the last one.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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