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Softa [21]
4 years ago
11

Graph the function f(x)=x^2+4-12

Mathematics
2 answers:
Paha777 [63]4 years ago
7 0
f(x)=x^2+4x-12=x^2+2x\cdot2+2^2-2^2-12=(x+2)^2-4-12=(x+2)^2-16


The coordinates of the vertex (-2; -16).


f(0)=0^2+4\cdot0-12=-12\to(0;-12)


The zeros:


f(x)=0\Rightarrow (x+2)^2-16=0\ \ \ |+16\\\\(x+2)^2=16\to x+2=\pm\sqrt{16}\\\\x+2=-4\ \vee\ x+2=4\ \ \ |-2\\\\x=-6\ \vee\ x=2\\\\(-6;\ 0);\ (2;\ 0)



son4ous [18]4 years ago
6 0
Hope this helps you
i assumed you meant
x {}^{2}  + 4x - 12

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