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Lana71 [14]
3 years ago
15

HELP PLEASE!!! :( I REALLY NEED HELP ASAP!! Thank you and stay safe!

Mathematics
2 answers:
Mkey [24]3 years ago
6 0

Answer:

a = 6, b = -2, c = 3

Step-by-step explanation:

6x² - 2x + 3 = 0

a = 6, b = -2, c = 3

kondaur [170]3 years ago
3 0

Answer:

a= 6, b=-2, and c=3

Step-by-step explanation:

Put the equation in:

ax^2+bx+c=0

To do this, add 3 to both sides

6x^-2x=-3

6x^-2x+3=0

Now, compare the equation to

ax^2+bx+c=0

6x^-2x+3=0

a=6, b= -2, and c =3

You might be interested in
Instructions:Select the correct answer from each drop-down menu. ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17). ∆XYZ has
Akimi4 [234]

to compare the triangles, first we will determine the distances of each side

<span>Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
</span>Solving 

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

<span>AB = 6 units   BC = 11 units AC = 12.53 units
</span><span>∆XYZ  X(-10, 5), Y(-12, -2), and Z(-4, 15)
</span><span>XY = 7.14 units   YZ = 18.79 units XZ = 11.66 units</span>

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>MN = 6 units   NO = 11 units MO = 12.53 units
</span><span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).
</span><span>JK = 5 units   KL = 9 units JL = 10.30 units
</span><span>∆PQR  P(12, 3), Q(12, -2), and R(3, -2)
</span><span>PQ = 5 units   QR = 9 units PR = 10.30 units</span> 
Therefore
<span>we have the <span>∆ABC   and the </span><span>∆MNO  </span><span> 
with all three sides equal</span> ---------> are congruent  
</span><span>we have the <span>∆JKL  </span>and the <span>∆PQR 
</span>with all three sides equal ---------> are congruent  </span>

 let's check

 Two plane figures are congruent if and only if one can be obtained from the other by a sequence of rigid motions (that is, by a sequence of reflections, translations, and/or rotations).

 1)     If ∆MNO   ---- by a sequence of reflections and translation --- It can be obtained ------->∆ABC 

<span> then </span>∆MNO<span> ≅</span> <span>∆ABC  </span> 

 a)      Reflexion (x axis)

The coordinate notation for the Reflexion is (x,y)---- >(x,-y)

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>M(-9, -4)----------------->  M1(-9,4)</span>

N(-3, -4)------------------ > N1(-3,4)

O(-3,-15)----------------- > O1(-3,15)

 b)      Reflexion (y axis)

The coordinate notation for the Reflexion is (x,y)---- >(-x,y)

<span>∆M1N1O1  M1(-9, 4), N1(-3, 4), and O1(-3, 15).</span>

<span>M1(-9, -4)----------------->  M2(9,4)</span>

N1(-3, -4)------------------ > N2(3,4)

O1(-3,-15)----------------- > O2(3,15)

 c)   Translation

The coordinate notation for the Translation is (x,y)---- >(x+2,y+2)

<span>∆M2N2O2  M2(9,4), N2(3,4), and O2(3, 15).</span>

<span>M2(9, 4)----------------->  M3(11,6)=A</span>

N2(3,4)------------------ > N3(5,6)=B

O2(3,15)----------------- > O3(5,17)=C

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

 ∆MNO  reflection------- >  ∆M1N1O1  reflection---- > ∆M2N2O2  translation -- --> ∆M3N3O3 

 The ∆M3N3O3=∆ABC 

<span>Therefore ∆MNO ≅ <span>∆ABC   - > </span>check list</span>

 2)     If ∆JKL  -- by a sequence of rotation and translation--- It can be obtained ----->∆PQR 

<span> then </span>∆JKL ≅ <span>∆PQR  </span> 

 d)     Rotation 90 degree anticlockwise

The coordinate notation for the Rotation is (x,y)---- >(-y, x)

<span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).</span>

<span>J(17, -2)----------------->  J1(2,17)</span>

K(12, -2)------------------ > K1(2,12)

L(12,7)----------------- > L1(-7,12)

 e)      translation

The coordinate notation for the translation is (x,y)---- >(x+10,y-14)

<span>∆J1K1L1  J1(2, 17), K1(2, 12), and L1(-7, 12).</span>

<span>J1(2, 17)----------------->  J2(12,3)=P</span>

K1(2, 12)------------------ > K2(12,-2)=Q

L1(-7, 12)----------------- > L2(3,-2)=R

 ∆PQR  P(12, 3), Q(12, -2), and R(3, -2)

 ∆JKL  rotation------- >  ∆J1K1L1  translation -- --> ∆J2K2L2=∆PQR 

<span>Therefore ∆JKL ≅ <span>∆PQR   - > </span><span>check list</span></span>
6 0
3 years ago
What’s the inequality?
Hitman42 [59]

Answer:

x: numbers of hot chocolate selling

y: numbers of apple cide selling

1x + 2y ≥ 240

2y ≥ 240 - x

y ≥ 120 - 0.5*x


7 0
3 years ago
In circle O, AP = √10, PB = x and BC = 3. Find the value of x.
Artyom0805 [142]

Answer:

The value of x is 2\ units

Step-by-step explanation:

we know that

Applying the  tangent-secant theorem

AP^{2}=PB*PC

substitute the values and solve for x

\sqrt{10}^{2}=x*(x+3)

10=x^{2}+3x

x^{2}+3x-10=0

using a graphing tool

to solve the quadratic equation

The solution is x=2\ units

see the attached figure

7 0
3 years ago
Perform the indicated operation. (2x + y)(3x2 + y)
UkoKoshka [18]

Answer:

Step-by-step explanation:

(2x+y)(3x²+y)=2x(3x²+y)+y(3x²+y)=6x³+2xy+3x²y+y²=6x³+3x²y+2xy+y²

5 0
3 years ago
Construct a mathematical model for the following real-life situations(make a table)
zhenek [66]

The mathematical model representing the scenarios described can be expressed as follows :

  • If n ≤ 8 ; A(n) = 31.25n
  • If n > 8 ; A(n) = 31.25 + 46.875(n - 8)

  • T(n) = 15 + 5(n - 1)

1.)

Amount paid per 8 hours at summer job = 250

Additional hours beyond, 8 hours = 1.5 × hourly rate

Let:

  • hourly rate = p
  • Number of hours worked = n
  • Amount earned as a function of n, A(n)

Hourly rate, p = (250 ÷ 8) = 31.25

Therefore, the hourly rate, p at the summer job = $31.25

Overtime pay = 1.5 × 31.25 = $46.875

Therefore,

If n ≤ 8 ; A(n) = 31.25n

If n > 8 ; A(n) = 31.25 + 46.875(n - 8)

2.)

Let :

  • Number of playing hours = n
  • Total amount charged as a function of n ; T(n)

Therefore,

T(n) = First hour fee + (charge per additional hour × number of additional hours)

T(n) = 15 + 5(n - 1)

Therefore, the models can be used to calculate the total earning and amount charged for any given hour value.

Learn more :brainly.com/question/18112348

6 0
2 years ago
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