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nadezda [96]
4 years ago
8

Which ordered pair (a, b) is a solution to the given system of linear equations? -2a+3b=14

Mathematics
2 answers:
Stels [109]4 years ago
6 0

Answer:

The solution of the system is the ordered pair (-13,-4)

Step-by-step explanation:

we have

-2a+3b=14 -----> equation A

a-4b=3 ----> equation B

Solve the system by elimination

Multiply by 2 both sides equation B

2(a-4b)=2(3)

2a-8b=6 ----> equation C

Adds equation A and equation C

-2a+3b=14\\2a-8b=6\\-------\\3b-8b=14+6\\-5b=20\\b=-4

<em>Find the value of a</em>

substitute the value of b in any equation (i take equation B)

a-4(-4)=3

a+16=3

a=-13

therefore

The solution of the system is the ordered pair (-13,-4)

cestrela7 [59]4 years ago
3 0

Answer:

(-13,-4)

Step-by-step explanation:

Trust Me, took the test

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ANEK [815]

2x+4y=0

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solve the equation

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divide by 2 on both sides

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4x+8y=7

substitute y with 0

4x+8(0)=7

solve the equation

4x+0=7

4x=7

divide by 4 on both sides

x=7/4 or x=1 3/4 or x=1.75

3x-7y=-29

2x+2y=6

solve the bottom equation

3x-7y=-29

x=3-y

substitute for x

3(3-y)-7y=-29

solve the equation

y=19/5

now substitute for y

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the possible solution of the system is the ordered pair

(x,y)=(-\frac{4}{5} ,\frac{19}{5})

3 0
4 years ago
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MrMuchimi
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borishaifa [10]

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4. Find the distance between the two points. Round to the nearest tenth if necessary.
Archy [21]

Answer:

Distance = 7.8 units

Step-by-step explanation:

In coordinate geometry, the distance between the 2 points is given by

Distance = \sqrt{(x1-x2)^{2} + (y1-y2)^{2} }

where (x1,y1) and (x2,y2) are coordinates of the 2 points.

Above the 2 points given are, (-2,-1) and (3,5).

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