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stealth61 [152]
3 years ago
12

why is there a bigger difference in temperature between January and July in Spokane than in Seattle ​

Geography
1 answer:
IrinaK [193]3 years ago
7 0

Answer:

Spokane and Seattle are located in the state of Washington. <u>Even though, Spokane is only 360 kilometers east of Seattle, there is a huge difference in temperature between January and July because of their distance from the pacific ocean.</u>

The temperature of Spokane and Seattle is influenced by the pacific ocean and the Olympic mountains around. Seattle is closer to the pacific ocean and the olympic mountains that keep the cities temperature lower while Spokane’s are more continental and far from the pacific ocean and the Olympic mountains that makes its temperature rise more.

Hence, the temperature of Spokane and Seattle is influenced by marine position.

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Explanation:

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How might the location of a city on a bay affect the economy of a city?
Naddik [55]

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It would boost the economy of those cities positively.

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1. It creates jobs and enhances local economies through activities like fisheries, seafood, etc.

2. It creates and improves water transportation. This includes seaports or boat transports.

3. It also serves the city in the aspect of revenue generation through tourism and recreation centers based on nature such as beach

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5 0
3 years ago
Choose all the answers that apply. Our solar system: is in a spiral galaxy no longer includes Pluto is made mostly of empty spac
Harman [31]

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4 0
3 years ago
ACT scores of a sample of UTC students are shown below. Student ACT Score A 22 B 28 C 20 D 21 E 28 F 23 G 26 a. Compute the mean
alisha [4.7K]

Solution :

a). Let  x denotes ACT scores.

ACT scores = $\{ 22,28,20,21,28,23,26 \} ; n = 7$

Mean, $(\overline x)=\frac{\sum x_i}{n}$

                $=\frac{168}{7}=24$

Sample variance, $S^2=\frac{1}{n-1}\left(\sum x_i^2-n\overline x^2 \right)$

                                  $=\frac{1}{6}(4098-7 \times 24^2)$

                                   $=\frac{66}{6}$

                                   = 11

b). To test whether or not variance of ACT scores of population (say $\sigma^2$) of the UTC students is significantly more than 8.

Consider the hypothesis :

$H_0: \sigma^2 \leq8$  vs $H_a: \sigma^2 >8$

It is a right tailed test and α = 0.05

We have

$x^2_{n-1} = \frac{(n-1)s^2}{\sigma^2}$

So test statics is

$x^2_7=\frac{(7-1)11}{8}$

   $=\frac{6 \times 11}{8}$

   = 8.25

Since our \text{test statistics is less than the critical value }and it falls in a acceptation region, hence we fail to reject $H_0$ and conclude that variance is not greater than 8 significantly.

8 0
3 years ago
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