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Crank
3 years ago
9

What is the least common multiple of 5 and 2

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0
10 is the least common multiple of 5 and 2
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An airplane pilot can see the top of a traffic control tower at a 20 degree angle of depression. the airplane is 5,000 feet away
daser333 [38]

The given question describes a right triangle with with one of the angles as 20 degrees and the side adjacent to the angle 20 degrees is of length 5,000 feet. We are looking for the length of the side opposite the angle 20 degrees.

Let the required length be x, then

\tan{20^o}=\cfrac{opp}{hyp}=\cfrac{x}{5,000}\\ \\ \Rightarrow x=5,000\tan{20^o}=1,819.85

Therefore, the height of the airplane above the tower is 1,819.85 feet.

8 0
3 years ago
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Reduce the ratio 8/12 to the lowest terms
Tanya [424]
The answer is 2/3
I hope this works for you :)
5 0
3 years ago
Help as soon as possible!!!!
yuradex [85]
2 =   1.313 is the right answer
3 =   24 is the right answer
4 =   27 is the right answer
7 0
3 years ago
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Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

  • \sin{\theta} < \cos{\theta} if 0^{\circ} < \theta;
  • \sin{\theta} > \cos{\theta} if 45^{\circ} < \theta;
  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
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Help help help help pls pls​
Tcecarenko [31]

Answer:

B. (3,0)(0 ,-6)

Step-by-step explanation:

What is intercept.?

Intercept are those points where a given line cuts across a given axis.

So for the equation y = 2x - 6

To find the intercept we will bear in mind that we are looking for two points.

The point where the line cuts both the x axis and the y axis .

And to determine that, we will set both x and y to be equal to zero and then solve for both.

So let x = 0

Y = 2x -6

Y = 2(0) -6

Y = -6

One point = (0 ,-6)

Let y = 0

Y = 2x -6

0 = 2x -6

6 = 2x

X = 3

One point = (3,0)

The two points are

(3,0)(0 ,-6)

6 0
3 years ago
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