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Crank
3 years ago
9

What is the least common multiple of 5 and 2

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0
10 is the least common multiple of 5 and 2
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Sally has 10 pounds she wants to buy 28 cans of soda which cost 28p each does she have enough money
Vladimir79 [104]

Answer:

Yes, Sally has enough money to buy 28 cans of soda.

Step-by-step explanation:

Yes, because £10 = 1000p

1000p / 28p = 35 cans

35 cans < 28 cans

So Sally has enough money for 28 cans.

4 0
2 years ago
Michael walked 30 meters in 20 seconds how many meters does he walk per second
Kipish [7]

Answer:

1.5 m/s or 1.5 meters per second

Step-by-step explanation:

Distance/Time=Speed

30m/20s= 1.5 m/s or 1.5 meters per second

6 0
3 years ago
Read 2 more answers
Please help 40 points
Natasha2012 [34]

Answer:

-2 5/9

Step-by-step explanation:

w + (-x) - 2/3

Let w = -5/9  and x = 4/3

-5/9  - 4/3 - 2/3

Get a common denominator

-5/9  -4/3*3/3  -2/3*3/3

-5/9  -12/9  -6/9

Add

-23/9

Change to a mixed number

-2 5/9

4 0
3 years ago
recipe for two dozen cookies calls for 234cups of sugar. How much sugar is needed to make one dozen cookies? A 38cupsover33, cup
gtnhenbr [62]

Answer:

117 cups

Step-by-step explanation:

two dozen cookies calls for 234cups of sugar

2 dozen cookies = 234 cups of sugar

How much sugar is needed to make one dozen cookies?

Let x = cups of sugar needed

1 dozen cookies = x cups of sugar

2 dozen cookies : 234 cups of sugar = 1 dozen cookies : x cups of sugar

2 : 234 = 1 : x

2 / 234 = 1 / x

Cross product

2*x = 234 * 1

2x = 234

x = 234 / 2

= 117 cups

Your options are wrong because none corresponds with the answer

3 0
2 years ago
There are approximately 3,000 bass in a lake. The population grows at a rate of 2% per year. Round answers to the nearest tenth.
Tamiku [17]

Answer:

years 1–4: 62.4 bass per year

years 5–8: 67.6 bass per year

Step-by-step explanation:

If the population in year n is ...

 p(n) = 3000·1.02^n

then the average rate of change from year 1 to year 4 is ...

 (p(4) -p(1))/(4 -1) = 3000(1.02^4 -1.02^1)/3 = 1020·(1.02^3 -1) ≈ 62.4

The average rate of change for years 1–4 is 62.4 bass per year.

For years 5–8, the rate of change is similarly computed:

 (p(8) -p(5))/(8 -5) = 3000(1.02^8 -1.02^5)/3 = 1000·1.02^5·(1.02^3 -1) ≈ 67.6

The average rate of change for years 5–8 is 67.6 bass per year.

5 0
3 years ago
Read 2 more answers
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