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Lostsunrise [7]
3 years ago
13

Where the square root of 7 be located on the number line below?

Mathematics
1 answer:
Semmy [17]3 years ago
7 0

Answer:  p and q

Step-by-step explanation: 2.64 x 2.64 = 6.9696

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Shelley ran 20 minutes and burned 130 calories. How many calories did Shelly burn per minute?
Savatey [412]
ANSWER

6.5 calories per minute.

EXPLANATION

To find the calories Shelley burned per minute, divide the total calories burned by the total minutes ran.

Calories burned for a minute

= \frac{130}{20}

This will give us,

= \frac{13}{2}

= 6.5 \: calories
3 0
3 years ago
Find the difference and reduce to the lowest terms 12 4/9 - 8 5/6 =
butalik [34]

Answer: 3\frac{11}{18}

<u>Turn 12 4/9 into an Improper Fraction</u>

Multiply 12*9 and get 108. Now add 4 and get 112.

12\frac{4}{9} =\frac{112}{9}

<u>Turn 8 5/6 into an Improper Fraction</u>

Multiply 8*6 and get 48. Now add 5 and get  53.

8\frac{5}{6} =53/6

<u>Find Common Denominator</u>

9: 9,18,27,36,45\\6: 6,12,18,24,30\\\CD=18

Your new problem: \frac{112}{18}-\frac{53}{18}

<u>Subtract</u>

<u></u>\frac{112}{18}-\frac{53}{18}=\frac{65}{18}<u></u>

<u></u>

<u>Simplify</u>

<u></u>\frac{65}{18} =3\frac{11}{18}<u></u>

6 0
3 years ago
Read 2 more answers
HELPPP PLEASEEE!!! I DON’T GET THIS AND I START SCHOOL TOMORROW
Lorico [155]
Queston 4: The range of the relation is : (-2,4)

Question 5: the domain of the relation is:
{2, 2.1, 5.1, 5.5, 6}

Question 6: The relation is not a function because it two of the x value have the same y values. Therefore it is not a function as it does not pass the vertical line test.
(-4, 0) and (-3, 0) both have 0 for the y coordinate. A function can’t have this.
4 0
3 years ago
CAN U PLZ HELP THANK YOU
Ulleksa [173]

Answer

second one

Step-by-step explanation:

3 0
3 years ago
You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%
bezimeni [28]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}

\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}

6 0
3 years ago
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