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makvit [3.9K]
3 years ago
15

Pre algebra please help me [email protec

ted]!!​

Mathematics
1 answer:
Sergio [31]3 years ago
3 0
You see the outlined rectangle? first find the perimeter to that.

you should get 20 feet.

now the hard part, the half circle. The dotted line on the top of it how’s the diameter of the circle, the diameter is 7 feet in this case.

now you must solve this equation to get the circumference: diameter • pi = circumference

Once you get your answer ( 21.98 ) then you divide by 2 ( because it’s half of a circle ).

Now you add 20 and the circumference of your half circle ( 10.99 ).

Your answer should be 30.99! :)
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kvasek [131]
<span>−8x+7y=25 is already in standard form, altho some people would prefer to re-write it as

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You have shared 4 equations here.  Next time, please separate them with commas or semi colons, or type just 1 equation per line, for increased clarity.  Thanks.</span>
5 0
3 years ago
EXPAND:
Sladkaya [172]

Answer:

\displaystyle  A) 5\log( {x}^{}   )  +   2 \log( {y}^{} )

Step-by-step explanation:

we would like to expand the following logarithmic expression:

\displaystyle   \log( {x}^{5}  {y}^{2} )

remember the multiplication logarithmic indentity given by:

\displaystyle \rm  \log( \alpha  \times  \beta ) \iff  \log( \alpha ) +  \log( \beta )

so our given expression should be

\displaystyle   \log( {x}^{5}   )  +    \log( {y}^{2} )

by exponent logarithmic property we acquire:

\displaystyle   5\log( {x}^{}   )  +   2 \log( {y}^{} )

hence, our answer is A

5 0
3 years ago
A certain piece of copper wire is determined
Sati [7]

Answer:

14

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mass of 100 centimeters of copper wire is 2.00

so, mass of 1 centimeter of copper wire will be \frac{2}{100}

hence, 14 centimeters of copper wire will provide .28 copper

8 0
3 years ago
One common factor of two numbers is 40. Another common factor is 10. If both numbers are less than 100, what are the two numbers
Viefleur [7K]
Only two numbers less than 100 have a factor of 40: 40 (1 x 40) and 80 (2 x 40). Since 40 is a factor of both 40 and 80, 10 must also be a factor - indeed, 40 = 4 x 10 and 80 = 8 x 10.

The two number must be 40 and 80.
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3 years ago
The three altitudes of ΔABC intersect at point F. Point F is the
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D.) Orthocenter.....
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