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makvit [3.9K]
3 years ago
15

Pre algebra please help me [email protec

ted]!!​

Mathematics
1 answer:
Sergio [31]3 years ago
3 0
You see the outlined rectangle? first find the perimeter to that.

you should get 20 feet.

now the hard part, the half circle. The dotted line on the top of it how’s the diameter of the circle, the diameter is 7 feet in this case.

now you must solve this equation to get the circumference: diameter • pi = circumference

Once you get your answer ( 21.98 ) then you divide by 2 ( because it’s half of a circle ).

Now you add 20 and the circumference of your half circle ( 10.99 ).

Your answer should be 30.99! :)
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Select the correct answer.<br> What are the solutions of this quadratic equation?<br> 25x^2 + 1 = 0
Llana [10]

Answer:

no solution because the square root of a negative number is not a real number d=-100

4 0
3 years ago
2 ( -2w - 1.2 + 7x) =
PSYCHO15rus [73]

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

8 0
4 years ago
Eddie needs 2 2/3 cups of flour for one batch of pancakes. How much flour does he need for 2 1/2 batches?
Alexxandr [17]

for 1 batch of pancake = 2 2/3 = 8/3 cups

for 2 1/2 = 5/2 pancake = 8/3 * 5/2 = 40/6 cups = 6 4/6 cups

7 0
3 years ago
Read 2 more answers
Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum
const2013 [10]

Answer:  The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

S=\sum_{i=1}^{\infty}15(4)^{i-1}.

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, \sum_{i=1}^{\infty}a_i is an infinite series, with complex coefficients a_i and we consider the following limit:

L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.

Then, the series will be convergent if  L < 1 and divergent if  L > 1.

For the given series, we have

a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.

So, the limit is given by

L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0
4 years ago
Read 2 more answers
Name numbers that’s round to 140,000 or 240,000 when rounded to the nearest ten thousand
andriy [413]

Answer:

150,000, 130,000

Step-by-step explanation:

well, 4 or below go down 5 and above go up so go from there

5 0
3 years ago
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