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4 years ago

Please Help

Mathematics

2 answers:

dimulka [17.4K]4 years ago

7 0

Answer:

x=-3.216 and y=2.514

Step-by-step explanation:

We plot the graphs of the equations:

-2x+5y=19

y= -5/6x - 1/6

The point of intersection of two graphs is the solution.

On seeing the graph we see that the solution is:

x=-3.216 and y=2.514

-13/4=-3.2 and 5/2=2.5

Hence, correct option is:

saw5 [17]4 years ago

5 0

Answer:

6y + 4x = 18 5/6

Step-by-step explanation:

-2x+5y=19

y= -5/6x - 1/6

Combine the xs

Combine the ys

Combine the whole numbers

6y + 4x = 18 5/6

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2/3 divided by 1/12 on number line

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Jill weighs 120 pounds and is gaining ten pounds each month. Paris weighs 150 pounds and is gaining 4 pounds each month. How man

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Answer:

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Step-by-step explanation:

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3 years ago

Select the simplification that accurately explains the following statement.

lutik1710 [3]

Answer:

Option (b) is correct.

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}=2^{1}=2$

Step-by-step explanation:

Given: $(2^\frac{1}{4} )^4$

We have too choose the correct simplification for the given statement.

Consider $(2^\frac{1}{4} )^4$

Using property of exponents, $(a^m)^n=a^m\times a^m\times a^m\times ....\times (n\ times)$

We have,

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}$

Again applying property of exponents $a^m\times a^m=a^{n+m}$

We have,

$(2^\frac{1}{4} )^4=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}$

Simplify, we have,

$(2^\frac{1}{4} )^4=2^{\frac{4}{4}}$

we get,

$(2^\frac{1}{4} )^4=2^{1}=2$

Thus, $(2^\frac{1}{4} )^4=2$

Option (b) is correct.

8 0

3 years ago

Read 2 more answers

What is the following product? ^3 square root 24 times ^3 square root 45

torisob [31]

Answer:

$6 \sqrt[3]{5}$

Step-by-step explanation:

For the problem, $\sqrt[3]{24} *\sqrt[3]{45}$ , use rules for simplifying cube roots. Under the operations of multiplication and division, if the roots have the same index (here it is 3) you can combine them.

$\sqrt[3]{24} *\sqrt[3]{45} = \sqrt[3]{24*45}$

You can multiply it out completely, however to simplify after you'll need to pull out perfect cubes. Factor 24 and 45 into any perfect cube factors which multiply to each number. If none are there, then prime factors will do. You can group factors together such as 3*3*3 which is 27 and a perfect cube.

$\sqrt[3]{24*45} =\sqrt[3]{3*8*5*3*3} = 6 \sqrt[3]{5}$

7 0

3 years ago