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ELEN [110]
3 years ago
7

Explain how you can round 25.691 to the greatest place.

Mathematics
1 answer:
nadezda [96]3 years ago
4 0
You have to round it to the nearest hundreds
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A study is done by a community group in two neighboring colleges to determine which one graduates students with more math classe
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Answer:

t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890  

The p value for this case would be:

p_v =P(t_{18}>0.890)=0.193  

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

Step-by-step explanation:

Information given

\bar X_{1}=4 represent the mean for sample A

\bar X_{2}=3.5 represent the mean for sample B

s_{1}=1.5 represent the sample standard deviation for A

s_{2}=1 represent the sample standard deviation for B  

n_{1}=11 sample size for the group A

n_{2}=9 sample size for the group B  

\alpha=0.1 Significance level provided

t would represent the statistic

Hypothesis to test

We want to verify if the student who graduates from college A has taken more math classes, on the average, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2} \leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=11+9-2=18  

Replacing we got:

t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890  

The p value for this case would be:

p_v =P(t_{18}>0.890)=0.193  

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

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3 years ago
Please help it confuses me ( STEPS NEEDED)
Bezzdna [24]
10^{8}x(2.5x10 + 5.3X1) = 10^{8}x(25 + 5.3) = 10^{8}x30.3 =
 10^{7}x303.
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