Answer:
Option b
Step-by-step explanation:
To solve this problem use the law of the sines.
We have 2 angles of the triangle and one of the sides.
The law of the sines is:
Then:
Answer:
6
Step-by-step explanation:
You must find the least common multiple of their schedules.
The numbers 3 and 2 are their own prime factors, so the least common multiple of 3 and 2 is 6.
Six weekends must pass until they can both have someone over on the same night.
The number line below shows that the first time their sleepovers coincide is Week 6.
Thirty-four decimal point eighty-two
Answer:
12 feets
Step-by-step explanation:
Let the area of the pool be Length×width
There will be 2lengths and 2widths as well so the perimeter of the pool will be the addition of all the sides of the pool i.e 2L + 2W = 96... (1)
And since the length of the pool is 3 times its width, we have
L = 3W... (2)
Substituting equation 2 into 1 to get the width 'W'
2(3W) + 2W = 96
6W + 2W = 96
8W = 96
W = 96/8
W = 12feets
The width of the pool is 12feets
Yes, they are independent. First of all, we know that P(A) = 1/4, P(B) = 2/5, and P(A and B) = 1/10. To know if two events are independent, the following questions must be true: P(A)*P(B) = P(A and B). So since (1/4)*(2/5) = 2/20 which equals 1/10, these events are independent
