Answer:
1 . The stage on the first meiotic division when the homologous chromosomes move to opposite poles but the sister chromatids remain together
: b. Anaphase I
2 . The stage in the second meiotic division where sister chromatids migrate to opposite poles
: c. Anaphase II
3 . A structure on the chromosome that holds a pair of chromatids together during replication
: f. centromere
4 . A double-stranded chromosome following replication attached by a centromere
: d. chromatid
5 . A condition where non-sister chromatid of homologous chromosomes exchange genes
: e. crossing over
6 . The stage in the first meiotic division where the homologous chromosomes line up as a pair
: a. Metaphase I
7 . The stage in the second meiotic division where the chromatid pair lines up at the equator of the cell: g. Metaphase II
Explanation:
DNA replication occurs during the S phase of the interphase of the cell cycle. The replicated DNA molecules are accommodated in two sister chromatids of a chromosome that are held together by a centromere.
During prophase I, the chromatids of a homologous chromosome pair exchange a genetic segment. This process is called crossing over. It generates recombinant chromatids with new combinations of genes.
Metaphase I of meiosis I includes the alignment of homologous pairs of chromosomes at the cell's equator. This is followed by separation and movement of homologous chromosomes to the opposite poles of the cell during anaphase I.
Metaphase II of meiosis II includes the alignment of individual chromosomes, each with two sister chromatids, on the cell's equator. During anaphase II, splitting centromere separates the sister chromatids which then move to the opposite poles of the cell.
Answer:
The energy that was not passed on the next tropic level is lost as heat
Explanation:
In an ecosystem flow of energy occur from one tropic level to the next one as the organism of one tropic level eats another organism belongs to the tropic level that is lower from that of previous one.
The 10% of total energy of one tropic level is passed to the next tropic level the rest of the energy is lost as heat in the environment.
I'm pretty sure that it's C. I'm not quite sure though.
POH = - log[OH^-]
pOH = - log[10^-6]
pOH = - (-6)
pOH = 6
knowing the ionization equation between pH and pOH in a solution at T = 25 degrees Celsius.
pH + pOH = 14
pH = 14 - pOH
pH = 14 - (6)
pH = 8.
I believe the pH of a substance with 10^-6 M of OH, would be 8.
Answer:
A. Person to person.
Explanation:
The graph shows that the disease spreads slowly at first, then rapidly, and slowly at the end. This pattern of transmission is most characteristic of a disease spread from one person to the next. When only one person has the disease, the rate of transmission is slow because that person may only meet a few others. But as the number of people with the disease increases, the number of meetings that spread the disease also increase. At this time, the disease can spread very rapidly. The disease spreads more slowly again when there are only a few people remaining that do not have the disease. With foodborne and airborne diseases, the rate of disease spread is most rapid when the disease first arises and the greatest number of possible victims are available. Graphs of foodborne and airborne transmission show the greatest rate of disease spread at the start of the outbreak.
FYI: This isn't my explanation this is the explanation the question gives! :)
