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aliya0001 [1]
3 years ago
13

Find cos B. A. 41/40 B. 9/41 C. 40/41 D. 9/40

Mathematics
2 answers:
Sphinxa [80]3 years ago
6 0
B it connect to the angles
Juli2301 [7.4K]3 years ago
3 0
CosB = side adjacent to B/hypotenuse = BC/AB = 9/41 


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If the length of a rectangle is 5 m more than its width find the values of length and width if the area of a rectangle is 500 m²
astra-53 [7]

Answer:

Length of the rectangle  =25

width of the rectangle  = 20

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'x' be the width of the rectangle

Given that the length of a rectangle is 5 m more than its width

Given that Area of the rectangle = 500m²

length of a rectangle = x +5

width of a rectangle = x

<u><em>Step(ii):-</em></u>

Area of the rectangle = length × width

             500 = x ( x+5)

          x² + 5 x = 500

      ⇒  x² + 5 x - 500 =0

      ⇒  x² +25x - 20 x - 500 =0

    ⇒  x( x+25) -20(x+25) =0

  ⇒  (x-20)(x+25) =0

 ⇒  x =20 and x=-25

we can choose x =20

<u><em>Step(iii):-</em></u>

Length of the rectangle = x +5 = 20 +5 =25

width of the rectangle  = 20

<u><em>Final answer</em></u>:-

Length of the rectangle  =25

width of the rectangle  = 20

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3. 2x-28=-16

4. 2x=12

5. x=6

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