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aliya0001 [1]
3 years ago
13

Find cos B. A. 41/40 B. 9/41 C. 40/41 D. 9/40

Mathematics
2 answers:
Sphinxa [80]3 years ago
6 0
B it connect to the angles
Juli2301 [7.4K]3 years ago
3 0
CosB = side adjacent to B/hypotenuse = BC/AB = 9/41 


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The net of a square pyramid is shown below:
xxMikexx [17]
The surface area is 24
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3 years ago
Simplify each equation, then solve. 1) log 2 128=x
NikAS [45]
\log _{ 2 }{ 128 } =x\\ \\ \log _{ 2 }{ \left( { 2 }^{ 7 } \right)  } =x\\ \\ 7\cdot \log _{ 2 }{ 2 } =x

\\ \\ 7\cdot 1=x\\ \\ \therefore \quad x=7
4 0
3 years ago
Read 2 more answers
A storm moves at a rate of 8 miles per hour. It is 200 miles away from Freeport and headed directly for this town. The equation
Eduardwww [97]

Pls see answer below.

Step-by-step explanation:

In this case, our slope is -8. This means that every hour, the storm is getting closer to the town by 8 miles per hour.

Our y-intercept is 200, which means that its' initial position is 200 miles away from the town.

Hope this helped.

7 0
2 years ago
Consider an experiment with a deck of 52 playing cards, in which there are 13 cards in each suit, two suits are black, and two s
lakkis [162]

Answer:

<u>P (E1) = 1/2 or 50%</u>

<u>P (E2) = 3/13 or 23%</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of playing cards = 52

Number of suits = 4

Number of cards per suit = 13

Number of black suits = 2

Number of red suits = 2

2.  Suppose E1 = the outcome is a red card and E2 = the outcome is a face card (K, Q, J). Determine P(E1 or E2).

P (E1) = Number of red cards/Total of playing cards

P (E1) = 26/52 = 1/2 = 50%

P (E2) = Number of face cards/Total of playing cards

P (E2) = 12/52 = 3/13 = 23%

8 0
3 years ago
Read 3 more answers
An unfair coin with​ Pr[H] = 0.2 is flipped. If the flip results in a​ head, a marble is selected at random from a urn containin
satela [25.4K]
Normally when dealing with coins the probability of getting heads or tails is 0.5 each. However in this case since its an unfair coin, the probability of getting heads is 0.2. 
H - head 
T - tails
R - red marble
pr (H) = 0.2
urn
6 red and 4 blue
pr (T)   = 0.8
urn
3 red and 5 blue

when heads is obtained 
red - 6/10 -0.6
blue - 4/10 - 0.4
therefore when multiplying with 0.2 probability of getting heads
pr (R ∩ H) red - 0.6*0.2 = 0.12

when tails is obtained 
red - 3/8 - 0.375
blue - 5/8 - 0.625
when multiplying with 0.8 probability of getting tails
pr (R ∩ T) red - 0.375 * 0.8 = 0.3

using bayes rule the answer can be found out, 
the following equation is used;
pr (H | R) = pr (R ∩ H) / {pr (R ∩ H) + pr (R ∩ T)}
               = 0.12 / (0.12 + 0.3)
               = 0.12 / 0.42
               = 0.286
the final answer is 0.286
6 0
3 years ago
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