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2 years ago

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For what value of x is this equation true? 10x−2(x+6)=52 10x−2(x+6)=52 A x=5 x=5 B x=5 3 4 x=534 C x=7 1 9 x=719 D x=8 x=8For wh

at value of x is this equation true? 10x−2(x+6)=52 10x−2(x+6)=52 A x=5 x=5 B x=5 3 4 x=534 C x=7 1 9 x=719 D x=8 x=8

1 answer:

insens350 [35]2 years ago

7 0

Answer:

x = 8

Step-by-step explanation:

10x - 2 (x + 6) = 52

Let X become 8

10 (8) - 2 (8 + 6) = 52

80 - 2 (14) = 52

80 - 28 = 52

52=52

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Given the piece wise function show below, select all that are true

NeTakaya

Answer:

Option (C) and (D)

Step-by-step explanation:

Given piecewise function is,

f(x) = 2x, x < 1

5, x = 1

$x^{2}$ , x > 1

Option (A),

x = 5 means x > 1

So the function will be,

f(x) = $x^{2}$

f(5) = (5)²

= 25

Therefore, f(5) = 1 is not correct.

Option (B),

x = -2 means x < 1

f(x) = 2x will be applicable.

f(-2) = 2(-2) = -4

Therefore, f(-2) = 4 is not correct.

Option (C)

For x = 1,

f(1) = 5

Therefore, f(1) = 5 is the correct option.

Option (D)

x = 2 means x > 1 and the function defined will be,

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f(2) = 2²

= 4

Therefore, f(2) = 4 will be the correct option.

Options (C) and (D) will be the answer.

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2 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

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7 0

2 years ago

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svetlana [45]

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2 years ago

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photoshop1234 [79]

Step-by-step explanation:

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2 years ago

A pair of equations is shown below:

Elan Coil [88]

So, both equations are essentially linear equations.
Linear equations are written in the format y = mx+b, where m represents the slope/slope intercept and b represents the y-intercept.
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y = mx +b
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therefore;

y = 6x - 4
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The coordinates of the point where the lines are crossed are the solution to the system of linear equations.

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***look at the img for graph reference***

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2 years ago