Answer:
See proof below.
Step-by-step explanation:
True
For this case we need to use the following theorem "If 
are eigenvectors of an nxn matrix A and the associated eigenvalues 
are distinct, then 
are linearly independent". Now we can proof the statement like this:
Proof
Let A a nxn matrix and we can assume that A has n distinct real eingenvalues let's say 
From definition of eigenvector for each one 
needs to have associated an eigenvector 
for 
And using the theorem from before , the n eigenvectors 
are linearly independent since the 
are distinct so then we ensure that A is diagonalizable.
The answer:
the full question is as follow:
if A+B-C=3pi, then find sinA+sinB-sinC
first, the main formula of sine and cosine are:
sinC = 2sin(C/2)cos(C/2)
sinA +sinB = 2sin[(A+B)/2]cos[(A-B)/2]
therefore:
sinA+sinB-sinC = 2sin[(A+B)/2]cos[(A-B)/2] - 2sin(C/2)cos(C/2)
sin[(A+B)/2] = cos(C/2)
2sin(C/2)cos(C/2) = cos[(A+B)/2
and
A+B-C=3 pi implies A+B =3 pi + C, so
cos[(A+B)/2] = cos [3 pi/2 + C/2]
and with the equivalence cos (3Pi/2 + X) = sinX
sinA+sinB-sinC = cos(C/2)+ sin(C/2)
So,
The circumference of a circle is
Substitute 15 for d
47.1
47
Your hand would move 47 inches.
Answer:
t^12
Step-by-step explanation:
Because both multiplicands are negative, their product will be positive. Both multiplicands are to the same base: t.
Therefore, the product is t^(7 + 5), or t^12.
