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Annette [7]
3 years ago
9

How do I simplify 7 to the power of 1

Mathematics
1 answer:
Savatey [412]3 years ago
8 0

\huge\boxed{7}

Any number to the power of 1 is itself. So, 7^1 = \boxed{7}.

Here are some more examples:

382^1 = 382

0^1 = 0

\pi^1 = \pi

You might be interested in
Let C be between D and E. Solve for x <br> DC = 5x + 8<br> CE = 3x + 5<br> DE = 61
morpeh [17]
DE/2 = 30.5
CE=30.5
DC=30.5

3x + 5 = 30.5
3x = 30.5 - 5
3x = 25.5
25.5/3 =8.5
x=8.5
8 0
3 years ago
A rectangle length was 4 feet longer than triple the length of it width
wlad13 [49]
Length is 48 ft

The perimeter of a rectangle is equal to the sum of all side’s.
2(lengths)+2(widths)= perimeter
Length=3x+4
Now given the perimeter of 140
3(3x+4)+3(x)=140
9x+12+3x=140
12x+12=140
12x=128
X= 10.7
10.7 is the width

Length=3x+4
Length =3(10.6)+4
Length=31.8+4
Length=35.8
Answer = 35.8
This can only be answered if you were given a perimeter.
4 0
3 years ago
Write the equation of a parabola with focus at (1,-4) and a directrix at X=2
konstantin123 [22]

Answer:

The equation of a parabola is

x =  \frac{1}{4(f - h)} (y - k) ^{2}  + h

Step-by-step explanation:

(h,k) is the vertex and (f,k) is the focus.

Thus, f = 1, k = −4.

The distance from the focus to the vertex is equal to the distance from the vertex to the directrix: f - h = h - 2.

Solving the system, we get h = 3/2, k = -4, f = 1.

The standard form is:

x =  -  \frac{y ^{2} }{2}  - 4y -  \frac{13}{2}

The general form is:

2x +  {y}^{2}  + 8y + 13 = 0

The vertex form is:

x =  -  \frac{(y + 4) ^{2} }{2}  +  \frac{3}{2}

The axis of symmetry is the line perpendicular to the directrix that passes through the vertex and the focus: y = -4.

The focal length is the distance between the focus and the vertex: 1/2.

The focal parameter is the distance between the focus and the directrix: 1.

The latus rectum is parallel to the directrix and passes through the focus: x = 1.

The length of the latus rectum is four times the distance between the vertex and the focus: 2.

The eccentricity of a parabola is always 1.

The x-intercepts can be found by setting y = 0 in the equation and solving for x.

x-intercept:

( -  \frac{13}{2}  \: ,0)

The y-intercepts can be found by setting x = 0 in the equation and solving for y.

y-intercepts:

(0, - 4 -  \sqrt{3)}

(0, - 4 +  \sqrt{3)}

3 0
2 years ago
Jennifer $12 to spend on lunch and roller rink. Admission to the roller rink is $5.75 Jennifer estimates that she can buy a larg
den301095 [7]
She may or may not because it depends on how much is the food and drink
6 0
3 years ago
Read 2 more answers
Need help with Writeing the quadratic function with at two zero where x = ‒2 and x = 0.
Pachacha [2.7K]
We can create the equation like this:
(x +2) * (x +0)
x^2 + 2x + 0 = 0

8 0
3 years ago
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