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3 years ago

What two numbers add together to get -13 and multiply to get -30? They have to be the same numbers.

2 answers:

4 0

For this problem, we need to find 2 numbers who have a sum of -13 and when multiplied have a product of -30. Since the product of the two numbers is negative, one of the factors has to be negative.

We will start by finding factors of 30.

Factors are two numbers that when multiplied together equal 30.

The factors of 30: {1,2,3,5,6,10,15,30}

Now, we will find a pair of factors that will add up to -13. Remember that one of the factors will be negative.

Let's start off with our first pair of factors: 1 and 30.

1+30=31
-1+30=29
1-30=-29

As we can see, this pair of factors is not a solution to the problem.

Let's start off with the second pair of factors: 2 and 15

2+15=17
-2+15=13
2-15=-13

2 and -15 have a sum of -13 and a product of -30.

The solution to this problem is 2 and -15.

IceJOKER [234]3 years ago

3 0

The two number are +2 and -15.

If u add those two, u will get -13 and if u multiply them, u will get -30.

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Answer:

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And adding we got:

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Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.65)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

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Solution to the problem

For this case we want to find this probability:

$P(X \geq 8)= P(X=8) +P(X=9) +P(X=10)$

And we can find the individual probabilities like this:

$P(X=8)=(10C8)(0.65)^0 (1-0.65)^{10-8}=0.176$

$P(X=9)=(10C9)(0.65)^1 (1-0.65)^{10-9}=0.072$

$P(X=10)=(10C10)(0.65)^2 (1-0.65)^{10-10}=0.013$

And adding we got:

$P(X \geq 8)= P(X=8) +P(X=9) +P(X=10)= 0.176+0.072+0.013=0.262$

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