Answer:
x = 11
Step-by-step explanation:
distribute: 4x - 28 = 27 - x
add x to both sides: 5x - 28 = 27
add 28 to both sides: 5x = 55
divide 5 to both sides: x = 11
Suppose the peg is like a rectangular prism:
It will be a right triangle with two sides of 2 and 2 because the diameter is 4.
c=√(2²+2²)
c=2√2
so the width of the largest peg is 2√2 or 2.83 inch
<h3>Possible coordinates of R = -5 or 5</h3><h3>Possible coordinates of T = -7 or 7</h3>
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Explanation:
If we're on a number line, then R could be at either R = 5 or R = -5. This is so the distance from A to R is 5 units. Distance is never negative. You count out the spaces to get the distance, or use subtraction and absolute value.
Saying "distance from A to R is 5" can be written as AR = 5. Meaning segment AR is 5 units long.
Now if AT = 7, then T could be at 7 or -7 on the number line. The reasoning as similar as to why R could be at -5 or 5.
Answer:
0.02493
Step-by-step explanation:
We are to Find :
P(p > 0.12) ;
This is equivalent to:
1 - P(p ≤ 0.12)
Using the relation :
1 - P((p - po) / (√(po(1 -po)) / n))
1 -P((Z ≤0.12 -0.09) / (√(0.09(1 -0.09)) / 350))
1 -P((Z≤0.03 / (√(0.09(0.91))/350))
1 - P((Z≤0.03 / 0.0152970))
1 - P((Z≤1.96116)
1 - 0.97507 (from Z probability calculator)
= 0.02493
We can factor by grouping like so
3v^2 + 16v + 5
3v^2 + 15v + v + 5
3v(v + 5) + 1(v + 5)
(3v+1)(v+5)
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Check:
(3v+1)(v+5)
w(v+5) ... let w = 3v+1
vw + 5w
v(w) + 5(w)
v(3v+1) + 5(3v+1) .... plug in w = 3v+1
3v^2+v + 15v + 5
3v^2 + 16v + 5
We get the original expression again, which confirms the answer.
