Question

Y=4-3x÷x-5 Make X the subject

Answer 1

x = $\frac{(4 + 5y)}{(y + 3)}$

multiply both sides by (x - 5)

y(x - 5) = 4 - 3x

xy - 5y = 4 - 3x

collect terms in x on the left side of the equation and other terms on the right side.

add 3x to both sides

xy + 3x - 5 y = 4

add 5y to both sides

xy + 3x = 4 + 5y

take out x as a common factor on the left side

x(y + 3) = 4 + 5y

divide both sides by (y + 3)

x = $\frac{(4 + 5y)}{(y + 3)}$

Answer 2

Cross Multiply by 'x - 5'
Hence
y(x - 5) = 4 -3x
xy - 5y = 4 - 3x

Move all the terms containing an 'x' to one side of the equals and all the others to the opposite side.
xy + 3x = 4 + 5y
Factor out 'x'
x(y + 3) = 4 + 5y
'Cross' divide by 'y + 3'
x = ( 4 + 5y) / (y + 3 )

'x' is now the subject.