Because everyone's DNA is different........
Answer: 20 fragments
Explanation:
This particular restriction enzyme has a 4 bp (base pair) recognition sequence therefore it will cleave once every 4ⁿ bases where n indicates the number pf bases in the recognition sequence.
- The recognition sequence is 4 bp therefore this restriction enzyme cleaves once every 4⁴ = 256 bases. This is the length of the restriction fragment.
- Calculate the number of fragments by dividing the total number of bases ( where you assume equal frequency of bases ie. A+T = C+G) by the length of the restriction base.
- therefore 5000bp/256bp = <u>19,53</u> now this number ca n be rounded up to 20.
- The expected number of fragments on the electrophoresis gel will be 20 fragments.
Answer:The correct answer is letter A.
Explanation: he is right
Your teacher gives you an unknown protist to classify that is currently inactive. The protist appears to have long lash-like
appendages protruding from its cell surface. Which kind of locomotion can we expect from this protist? (1 point)
The appendages of this protist will move in a dragging motion that actively pulls the protist forward.
O The appendages of this protist will move in a sweeping motion like oars to actively propel the protist forward.
The appendages of this protist will move back and forth like a wagging tail to actively propel the protist
forward
O The appendages of this protist are not functional, and the protist moves passively via environmental forces.
