Answer:
7.75
Step-by-step explanation:
Answer:
Check below, please.
Step-by-step explanation:
Hi, there!
Since we can describe eccentricity as 
a) Eccentricity close to 0
An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

b) Eccentricity =5

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

c) Eccentricity close to 1
In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.


Answer:
B
Step-by-step explanation:
it is an exponential function
I'm pretty sure it would have to be 155. Considering a flat line has an angle of 180 and if you subtract 180 from 25 you get 155.
Hey.
I hope that you're familiar with P.E.M.D.A.S :)
applying PEMDAS :
2 + 6 × 5 ÷ 8
2 + 30 ÷ 8
32 ÷ 8 = 4
Hence, The required answer is 4
Thanks.