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3 years ago

Help answer this.........

Mathematics

1 answer:

rusak2 [61]3 years ago

5 0

Answer:

DELETE IT AGAIN!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

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7.5g of sugar is needed for every cake made how much sugar is needed for 10 cakes

lana [24]

Answer:

75 g

Step-by-step explanation:

i think as this a recipe propotional so you have to find how much sugar is needed for 1.g

4 0

3 years ago

How does multiplication relate to time conversion?

anygoal [31]

That would first be a conversion factor is a number used to change one set of units to another, by multiplying or dividing. when a conversion is necessasry

8 0

3 years ago

WILL GIVE BRAINLIEST, THANKS, AND 5 STARS! PLEASE HELP ME!

Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

Method 1

Apply Difference of Two Squares Formula: $a^2-b^2=(a+b)(a-b)$

Given $x^2-16=0$

Rewrite 16 as 4²

Therefore, $a^2=x^2$ and $b^2=4^2$

$\implies a = \sqrt{x^2}=x$

$\implies b=\sqrt{4^2} =4$

$\implies x^2-16^2=(x+4)(x-4)$

$\implies (x+4)(x-4)=0$

$\implies (x+4)=0 \implies x=-4$

$\implies (x-4)=0 \implies x=4$

Method 2

Given equation:

$x^2-16=0$

Add 16 to both sides:

$\implies x^2-16+16=0 + 16$

$\implies x^2=16$

Square root both sides:

$\implies \sqrt{x^2}=\sqrt{16}$

$\implies x=\pm4$

Therefore, x = -4, x = 4

6 0

2 years ago

Petes dog weighed 30 pounds it then lost 16% of it's weight how much did pete lose

Vlad [161]

Answer:

The dog lost 4.8 pounds! Goodluck!

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A certain paper suggested that a normal distribution with mean 3,500 grams and a standard deviation of 560 grams is a reasonable

Natalka [10]

Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19

Step-by-step explanation:

Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = birth weights of babies

µ = mean weight

σ = standard deviation

From the information given,

µ = 3500 grams

σ = 560 grams

We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as

P(x > 4000) = 1 - P(x ≤ 4000)

For x = 4000,

z = (4000 - 3500)/560 = 0.89

Looking at the normal distribution table, the probability corresponding to the z score is 0.81

P(x > 4000) = 1 - 0.81 = 0.19

5 0

3 years ago