All categories

2 years ago

The movie lasted 105 minutes if the movie started at 1:15 pm at what time did it end?

Mathematics

1 answer:

Valentin [98]2 years ago

4 0

3:30 because 105/60 equals 2.15
then you just add the time to the starting time

You might be interested in

Find the radius of each figure. round to the nearest tenth.

k0ka [10]

Answer:

8.25475 m

Step-by-step explanation:

pi*r^3 is the formula for a sphere.

Using this, pi is a nmber (about 3.14) and we only don't know the radius, but we know what it equals.

pi*r^3=1,767.1

First divide by pi, then get ride of the cube by cube rooting both sides.

The cube root of 1767.1/pi (remember to cube root both denominator and numberator!!!) is about 8.25475 m

6 0

3 years ago

Solving proportion 10\8=n\10

Zanzabum

$\frac { 10 }{ 8 } =\frac { n }{ 10 } \\ \\ 10\cdot \frac { 10 }{ 8 } =\frac { n }{ 10 } \cdot 10\\ \\ \frac { 100 }{ 8 } =n$

$\\ \\ n=\frac { 4\cdot 25 }{ 4\cdot 2 } \\ \\ \therefore \quad n=\frac { 25 }{ 2 }$

6 0

3 years ago

Read 2 more answers

Can help me with this?

Tanzania [10]

Answer:I’m sorry this is hard I don’t think I have the right answer chose C

Step-by-step explanation:

3 0

2 years ago

Write 5.1• 10 to the power of 4

VashaNatasha [74]

Answer:

6765201

Step-by-step explanation:

(5.1*10)^4

51^4

6765201 (USED CALCULATOR)

5 0

3 years ago

Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random

Katen [24]

Answer:

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

Given

$n = 200$

$x_1 = 34$ -- City C

$x_2 = 54$ --- City K

Required

Determine the 90% confidence interval

This is calculated using:

$CI = \bar x \± z\frac{\sigma}{\sqrt n}$

Calculating $\bar x$

$\bar x = \bar x_1 - \bar x_2$

$\bar x = \frac{x_1}{n} - \frac{x_2}{n}$

$\bar x = \frac{34}{200} - \frac{54}{200}$

$\bar x = 0.17 - 0.27$

For a 90% confidence level, the z-score is 1.65. So:

$z = 1.65$

Calculating the standard deviation $\sigma$

$\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }$

So:

$\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }$

$\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}$

So:

$CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}$

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

7 0

2 years ago