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3 years ago

The movie lasted 105 minutes if the movie started at 1:15 pm at what time did it end?

Mathematics

1 answer:

Valentin [98]3 years ago

4 0

3:30 because 105/60 equals 2.15
then you just add the time to the starting time

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Identify the initial amount and the growth rate of the following:<br> Y = 9.8 (1.35)^t

stiv31 [10]

Assuming t is a time unit.
The initial amount is when t = 0, so it is 9.8 * 1 = 9.8. The growth rate is how much the amount goes up by for every increase of 1 in t. This is 1.35 because that is the part being affected by t. we plug in 0 for t to get 9.8 as the initial amount. The growth rate is just 135% factor, or 35% more each time, because 1.35 is the base of the exponent.

4 0

3 years ago

Describe the relationship between the value of the digits in the number 9,999,999

algol [13]

9 999 999 in words is read as nine million, nine hundred and ninety-nine thousand, and nine hundred and ninety-nine

By partitioning, we can write 9 999 999 as follow
9 000 000 + 900 000 + 90 000 + 9000 + 900 + 90 + 9

If we start at the first digit of '9' on the left, the next digit is ten times smaller than the previous one.

4 0

3 years ago

Due to a packaging error, 4 cans labeled diet soda were accidentally filled with regular soda and placed in a 12 pack carton of

Sophie [7]

Answer:

Probability that both cans were regular soda = $\frac{1}{11}$

Step-by-step explanation:

Probability = $\frac{Desired outcome}{Total possible outcomes}$

We are given 12 total number of cans; 4 cans have been accidentally filled with diet soda.

Probability that first can is a regular soda:

Outcome that first can is a regular soda will give us the number of regular soda available which are 4

Using formula of probability

Total possible outcomes are, n(total) = 12

Desired outcome: 4 (cans of regular soda)

P(1st can) = $\frac{4}{12}$ = $\frac{1}{3}$

Probability that 2nd can is a regular soda:

<em>As we have already taken a can of regular soda from the pack, the total soda in the pack now 11 and the regular soda left are 3.</em>

Total possible outcomes are, n(total) = 11

Desired outcome: 3 (cans of regular soda as one has already been taken)

P(2nd can) = $\frac{3}{11}$

Probability that both cans are regular soda:

P(both) = P(1st can) × P(2nd can)

= $\frac{1}{3} * \frac{3}{11}$

= $\frac{1}{11}$

3 0

4 years ago

Read 2 more answers

I need help with 1 and 2 please :(

saveliy_v [14]

1 equals 0.3
2 equals 1.25

6 0

3 years ago

Read 2 more answers

PLLZZZZZZZ HELP!!!!!

Gnoma [55]

The answer is 8 and heres why:

$64^{\frac{3}{6}} \\\frac{3}{6}=\frac{1}{2} \\ \\64^{\frac{1}{2}} \\ \\\mathrm{Factor\:the\:number:\:}\:64=8^2 \\\left(8^2\right)^{\frac{1}{2}} \\ \\\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc} \\\left(8^2\right)^{\frac{1}{2}}=8^{2\cdot \frac{1}{2}}=8$

And that is how you solve this promblem :-)

7 0

3 years ago