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konstantin123 [22]
3 years ago
14

A spinner has four equal sectors that are red, blue, yellow, and green. Ethan spins the spinner twice. What is the probability t

hat it lands on the same color for both spins? Write your answer as a decimal.
Mathematics
2 answers:
sergey [27]3 years ago
6 0
The probability is 1/16 for each color

and 4/16 total

good luck
Liono4ka [1.6K]3 years ago
4 0
There are 4 sides, You have a \frac{1}{4} chance of landing on one color like blue, or red for just one spin. You have a \frac{2}{4} to land on the same color for both spins. This as a decimal is 0.5 chance of landing on the same color for both spins
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5.
Sunny_sXe [5.5K]

distance= rate ÷ time

time= rate ÷ distance

time= 200 km/hr ÷ 1400 km

time= 1/7 hr or 0.1428... hr

4 0
3 years ago
1. If <1 is 120 degrees , what is the measure of <2?
natali 33 [55]

Answer:

240

Step-by-step explanation:

2 is 1 + 1 so 120 + 120 must be the equivalent of 2.

5 0
3 years ago
Five dices are tossed together, what is the total number of outcome expected from this experiment?
Serga [27]
The total number of outcomes would be 6 ;) Hope this helps!
3 0
3 years ago
Please help me and I’ll give you brainiest!!!!!
algol [13]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
A square carpet of side length 9 feet is designed with one large shaded square and eight smaller, congruent shaded squares, as s
Pepsi [2]

Answer:

3\sqrt{3} + 72

Step-by-step explanation:

I attached an image to aid the understanding of the question.

Looking at the image, we see that the 8 shaded parts are congruent, as affirmed in the question as well. And we are told that T = 3, this implies that the area of the square with T as it's side is 9ft². Since all the 8 squares are congruenrt, it means each square has its area to be 9. Therefore, the total area of the 8 shaded squares will be:

9 \times 8 = 72ft^{2}

It remains the area of the shaded square with side S.

From the question, we have the following ratio:

\frac{9}{S} = \frac{S}{T}[\tex]But[tex]\frac{9}{S} = \frac{S}{3}[\tex]Multiplying through by 3S we have27 = S² and this gives:[tex]S = \sqrt{27} = 3\sqrt{3}

I did not add ± because length is always positive, so the case of negative is eliminated.

Now the areas of S is 3\sqrt{3}

Therefore, the total area of the shaded squares is

3\sqrt{3} + 72

3 0
3 years ago
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