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3 years ago

Type the correct answer in each box. Use numerals instead of words.

Mathematics

2 answers:

Alex_Xolod [135]3 years ago

6 0

Answer:

Step-by-step explanation:

Given that prices for a pair of shoes lie in the interval

[80,180] dollars.

Delivery fee 20% of price.

i.e. delivery fee will be in the interval [4, 9]

(1/20th of price)

Total cost= price of shoedelivery cost

Hence f(c) = c+c/20 = 21c/20

The domain of this function would be c lying between 80 to 180

So domain =[80,180]

---------------------------------

Amount to be repaid = 42 dollars

Once he received this amount, the price would be

105+42 =147

But since price range is only [21*80/20, 21*180/20]

=[84, 189]

Since now Albert has 147 dollars, he can afford is

[80,147]

Sonbull [250]3 years ago

4 0

Answer:

First answer: [80 , 180]

Second answer [80 , 147]

Step-by-step explanation:

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Write the given roots to quadraatic equation

german

Answer:

It's like solving a quadratic, but in reverse, and in this case you'll arrive at x2+x−12=0

Explanation:

We're going to go "backwards" with this problem - normally we're asked to take a quadratic equation and find the roots. So we'll do what we normally do, but in reverse:

Let's start with the roots:

x=3, x=−4

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x−3=0, x+4=0

Now we can set up the equation, as:

(x−3)(x+4)=0

We can now distribute out the 2 quantities:

x2+x−12=0

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3 years ago

62 divide 7 what remains number

yarga [219]

Answer:

Step-by-step explanation:

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3 years ago

Solve the equation for x in terms of c

Dovator [93]

$solve\:for\:x,\:\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}=\frac{5}{2}$

$\mathrm{Add\:}\frac{1}{4}\mathrm{\:to\:both\:sides}$

$\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}+\frac{1}{4}=\frac{5}{2}+\frac{1}{4}$

$\frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11}{4}$

$\mathrm{Multiply\:both\:sides\:by\:}3$

$3\cdot \frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11\cdot \:3}{4}$

$2cx+1=\frac{33}{4}$

$\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}$

$2cx+1-1=\frac{33}{4}-1$

$2cx=\frac{29}{4}$

$\mathrm{Divide\:both\:sides\:by\:}2c$

$x=\frac{29}{8c}$

<h3>Therefore, correct option is C. option.</h3><h3>C. x=29/8c</h3>

8 0

3 years ago

The midpoint of AB is M (0, -3). If the coordinates of AA are (2, 1) what are the coordinates of BB?

frez [133]

Answer:

B(-2, -7)

Step-by-step explanation:

Midpoint is (0, -3)

A(x₁, y₁) B(x₂, y₂)

A(2, 1)

$Midpoint = (\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2} )\\\\Midpoint = (\frac{2+ x_{2} }{2}, \frac{1 + y_{2} }{2} )$

$(0, -3) = (\frac{2+ x_{2} }{2}, \frac{1 + y_{2} }{2} )$

$\frac{2+ x_{2} }{2} = 0\\\\2 + x_{2} = 0\ \ \ \ times\ both\ sides\ by\ 2\\x_{2} = -2\ \ \ \ subtract\ both\ sides\ by\ 2$

$\frac{1 + y_{2} }{2} = -3\\\\1 + y_{2} = -6\ \ \ \ times\ both\ sides\ by\ 2\\y_{2} = -7\ \ \ \ subtract\ both\ sides\ by\ 1$

∴ B(-2, -7)

6 0

2 years ago

How do i solve that (2x+1)(x+4)

Slav-nsk [51]

There are 2 x’s so it’s 2x^2 + 9x because 2x4 is 8 + 1 x and then + 4 because you connect like terms so it would be 2x^2+9x+4

4 0

3 years ago

Read 2 more answers