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vovikov84 [41]
3 years ago
8

What is the factor in this equation? 3+(4r + y)

Mathematics
1 answer:
zlopas [31]3 years ago
8 0
The factors are 3 and (4r+y)

Hope this helps :)
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Add (-x^2-2x+6)+(-9x^2-7x+6)
77julia77 [94]

(-x²-2x+6)+(-9x²-7x+6) = -x²-2x+6-9x²-7x+6 = -10x² - 9x + 12

5 0
3 years ago
Solve for x<br> Can somebody plz answer this asap
Vitek1552 [10]

Answer:

A

Step-by-step explanation:

set them equal to each other and solve

8 0
3 years ago
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If he spends $2,000, then he has 1/6 of the original amount left. how much money did he have originally?
Elina [12.6K]
He had 3000 originally do 3000 divided by 1/6 and i got 3000 by 6 x 500
5 0
4 years ago
​Recently, a random sample of 2534 year olds was​ asked, "How much do you currently have in​ savings, not including retirement​
Tom [10]

The approximations of the mean and the standard deviation are 233.3 and 229.82, respectively

<h3>How to determine the mean?</h3>

The table of values is given as:

Savings Lower Limit Upper Limit     Frequency

0-199         0         199                       345

200-399   200   399                         97

400-599   400   599                         52

600-799   600   799                         21

800-999   800   999                         9

1000-1199 1000  1199                         8

1200-1399 1200  1399                      3

Rewrite the table to include the class midpoint and the frequency

x               f

99.5         345

299.5        97

499.5        52

699.5        21

899.5        9

1099.5        8

1299.5        3

The mean is calculated as:

\bar x = \frac{\sum fx}{\sum f}

So, we have:

\bar x = \frac{99.5* 345 + 299.5* 97 + 499.5* 52 + 699.5 * 21 + 899.5 * 9 +  1099.5 * 8 + 1299.5 * 3}{345 + 97 + 52 + 21 + 9 + 8 +3}

Evaluate

\bar x = 233.331775701

Approximate

\bar x = 233.3

Hence, the approximation of the mean is 233.3

<h3>How to determine the standard deviation?</h3>

The standard deviation is calculated as:

\sigma = \sqrt{\frac{\sum f(x - \bar x)^2}{\sum f}}

So, we have:

\sigma= \sqrt{\frac{(99.5-233.3)^2* 345 + (299.5-233.3)^2* 97 +...... + (1299.5 -233.3)^2* 3}{345 + 97 + 52 + 21 + 9 + 8 +3}

Evaluate

\sigma = 229.82

Hence, the approximation of the standard deviation is 229.82

Read more about mean and standard deviation at:

brainly.com/question/475676

#SPJ1

4 0
2 years ago
Which of the following items would be considered an asset? Select all that apply.
Anarel [89]
The answer is a or e
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4 years ago
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