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Zanzabum
3 years ago
9

Hi I really need help with this assignment plz

Mathematics
2 answers:
brilliants [131]3 years ago
6 0

the first option is the correct one


Dahasolnce [82]3 years ago
6 0

13/18 = 0.72

11/14 = 0.78

So 13/18 < (less than) 11/14.

Hope this Helps!!


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There is a bag with 6 marbles. Three marbles are blue, 2 are red and 1 is green. What is the probability that you will randomly
Dominik [7]

Answer:

Mike is not correct.

Step-by-step explanation:

The probability is an "out of" statement. meaning out of all 6 marbles if 2 are red how what is the probability of choosing a red marble the answer is 2 out of 6 or 1/3 or 0.3333333etc. For green the probability is 1 out of 6 or 1/6 or 0.16666666etc

8 0
3 years ago
Using the following figure, match the angles in the first column with their corresponding congruent angles in the second column.
Rus_ich [418]

Answer:

∠6 = ∠8

∠2 = ∠6

Step-by-step explanation:

Lines 'p' and 'q' are the parallel lines and line 'l' is a transversal line intersecting these lines at two distinct points.

By the property of alternate interior angles,

∠3 = ∠5

By the property of vertically opposite angles,

∠6 = ∠8

By the property of corresponding angles,

∠2 = ∠6

3 0
3 years ago
1. The ratio of students in 8th grade that preferred math
Marta_Voda [28]

Answer:

a.  180

Step-by-step explanation:

\frac{4x}{10} = \frac{72}{1}

cross-multiply:

4x = 720

x = 180

5 0
3 years ago
If the scale factor is 3/2, find the larger square missing side.A) 8 inch) 9 inch) 10 inch) 12 inch
ch4aika [34]

Answer:

B) 9

Step-by-step explanation:

6×3/2=9

5 0
2 years ago
Consider a rabbit population​ P(t) satisfying the logistic equation StartFraction dP Over dt EndFraction equals aP minus bP squa
maria [59]

Solution:

Given :

$\frac{dP}{dt}= aP-bP^2$         .............(1)

where, B = aP = birth rate

            D = $bP^2$  =  death rate

Now initial population at t = 0, we have

$P_0$ = 220 ,  $B_0$ = 9 ,  $D_0$ = 15

Now equation (1) can be written as :

$ \frac{dP}{dt}=P(a-bP)$

$\frac{dP}{dt}=bP(\frac{a}{b}-P)$    .................(2)

Now this equation is similar to the logistic differential equation which is ,

$\frac{dP}{dt}=kP(M-P)$

where M = limiting population / carrying capacity

This gives us M = a/b

Now we can find the value of a and b at t=0 and substitute for M

$a_0=\frac{B_0}{P_0}$    and     $b_0=\frac{D_0}{P_0^2}$

So, $M=\frac{B_0P_0}{D_0}$

          = $\frac{9 \times 220}{15}$

          = 132

Now from equation (2), we get the constants

k = b = $\frac{D_0}{P_0^2} = \frac{15}{220^2}$

        = $\frac{3}{9680}$

The population P(t) from logistic equation is calculated by :

$P(t)= \frac{MP_0}{P_0+(M-P_0)e^{-kMt}}$

$P(t)= \frac{132 \times 220}{220+(132-220)e^{-\frac{3}{9680} \times132t}}$

$P(t)= \frac{29040}{220-88e^{-\frac{396}{9680} t}}$

As per question, P(t) = 110% of M

$\frac{110}{100} \times 132= \frac{29040}{220-88e^{\frac{-396}{9680} t}}$

$ 220-88e^{\frac{-99}{2420} t}=200$

$ e^{\frac{-99}{2420} t}=\frac{5}{22}$

Now taking natural logs on both the sides we get

t = 36.216

Number of months = 36.216

8 0
4 years ago
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