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dimaraw [331]
3 years ago
7

Write and real-world problem that could be represented by the inequality below:

Mathematics
1 answer:
natima [27]3 years ago
7 0

Answer:

Tiffany has a number of skittles plus 655 watermelon sour patch kids. Compared to Jake, Jake has 5 times more skittles than Tiffany, plus 600 watermelon sour patch kids. Write an inequality to represent this scenario.

I hope this helped! :) If it was correct for your question please give me brainliest!

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In AKLM, the measure of ZM=90°, the measure of ZL=76°, and LM = 99 feet. Find
viktelen [127]

Answer:

99

Step-by-step explanation:

4 0
3 years ago
Simplify 24 ÷ (-2)(3) + 7Simplify 24 ÷ (-2)(3) + 7
Mnenie [13.5K]

Solving the expression 24\div (-2)(3) + 7 we get -29

Step-by-step explanation:

We need to simplify 24\div (-2)(3) + 7

Solving:

24\div (-2)(3) + 7

Using DMAS rule

=24\div(-2)*(3)+ 7

=-12*3+ 7

=-36+7

=-29

So, solving the expression 24\div (-2)(3) + 7 we get -29

Keywords: Solving the expression

Learn more about Solving the expression at:

  • brainly.com/question/5147732
  • brainly.com/question/2386054
  • brainly.com/question/11229113

#learnwithBrainly

7 0
4 years ago
Can someone please help me
Brrunno [24]
Hmmmm...... Are you a 6th grader? I remember doing these in 6th grade.
6 0
4 years ago
Read 2 more answers
Lucy made 3 cakes that each weighed 32 ounces. how many pounds of cake did lucy make
Anna11 [10]
There are 16 ounces in a pound. 3 x 32= 96
96/16=6

Lucy made 6 pounds of cake. Hope this helped!
5 0
3 years ago
Read 2 more answers
If you roll two six-faced dice together, you will get 36 possible outcomes. 4 pts 1. List all possible outcomes of the experimen
bezimeni [28]

Given:

Two dice are rolled together.

Total number of possible outcomes.

To find:

The list of total possible outcomes.

The probability of getting a sum of 11 in these outcomes.

The probability of getting a sum less than or equal to 4.

The probability of getting a sum of 13 or more.

Solution:

If two dice are rolled together, then the total number of possible outcomes is 36 and list of total possible outcomes is

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Sum of 11 in these outcomes = {(5,6),(6,5),(6,6)} = 3

The probability of getting a sum of 11 in these outcomes is

P(\text{sum=11})=\dfrac{3}{36}

P(\text{sum=11})=\dfrac{1}{12}

Therefore, the probability of getting a sum of 11 in these outcomes is \dfrac{1}{12}.

Sum less than or equal to 4 = {(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)} = 6

The probability of getting a sum less than or equal to 4 is

P({sum\leq 4})=\dfrac{6}{36}

P({sum\leq 4})=\dfrac{1}{6}

Therefore, the probability of getting a sum less than or equal to 4 is \dfrac{1}{6}.

Sum of 13 or more = empty set because maximum sum is 12.

The probability of getting a sum of 13 or more is

P(sum\geq 13)=\dfrac{0}{36}

P({sum\geq 13})=0

Therefore, the probability of getting a sum of 13 or more is 0.

8 0
3 years ago
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