Explanation:
KEY POINTS
Understanding work is quintessential to understanding systems in terms of their energy, which is necessary for higher level physics.
- Work is equivalent to the change in kinetic energy of a system.
- Distance is not the same as displacement. If a box is moved 3 meters forward and then 4 meters to the left, the total displacement is 5 meters, not 7 meters.
Here are a few example problems:
(1.a) Consider a constant force of two newtons (F = 2 N) acting on a box of mass three kilograms (M = 3 kg). Calculate the work done on the box if the box is displaced 5 meters.
(1.b) Since the box is displaced 5 meters and the force is 2 N, we multiply the two quantities together. The object’s mass will dictate how fast it is accelerating under the force, and thus the time it takes to move the object from point a to point b. Regardless of how long it takes, the object will have the same displacement and thus the same work done on it.
(2.a) Consider the same box (M = 3 kg) being pushed by a constant force of four newtons (F = 4 N). It begins at rest and is pushed for five meters (d = 5m). Assuming a frictionless surface, calculate the velocity of the box at 5 meters.
(2.b) We now understand that the work is proportional to the change in kinetic energy, from this we can calculate the final velocity. What do we know so far? We know that the block begins at rest, so the initial kinetic energy must be zero. From this we algebraically isolate and solve for the final velocity
Answer:
True!
Explanation:
Northern Japan has warm summers and very cold winters with heavy snow on the Sea of Japan side and in mountainous areas.
Eastern Japan has hot and humid summers and cold winters with very heavy snow on the Sea of Japan side and in mountainous areas.
Western Japan has very hot and humid summers (with temperatures sometimes reaching 35C or above) and moderate cold winters.
Okinawa and Amami have a subtropical oceanic climate. These areas have hot and humid summers (with temperatures rarely reaching 35C or above) and mild winters.
Answer:
(23,5) and (3,11)
Explanation:
first we need to use the midpoint formula which is:
( x1 +x2 / 2 , y1 + y2 / 2)
essentially what this formula does is take the average of the x coordinates and the average of the y coordinates to find the middle
we know the x coordinate of the midpoint is 13 and the y coordinate of the midpoint is 8
so now we substitute the values into the formula an
d solve
x1 = 3x + 2 y1 = 5
x2 = 3. y2 = 2y + 1
(3x + 2 + 3)/2 = 13 and (5 + 2y + 1)/2 = 8
solving each equation gives x = 7, and y = 5
finally we go to the original points and substitute in the values we found
(3x + 2, 5) = (3(7) + 2, 5) = (23,5)
(3, 2y + 1) = (3, 2(5) + 1) = (3, 11)