Write each function in function notation: a) = 5 + 2 b) = |3 − 1| c) = 2 + 5 − 8
2 answers:
You might be interested in
Using the t-distribution, it is found that since the p-value is greater than 0.01, there is no evidence that the new machine should be rejected at the 0.01 significance level.
<h3>What are the hypothesis tested?</h3>At the null hypothesis, it is tested if the average is not less than 25, that is:
At the alternative hypothesis, it is tested if the average is less than 25, that is:
The test statistic is given by:
The parameters are:
is the sample mean.
is the value tested at the null hypothesis.
- s is the standard deviation of the sample.
- n is the sample size.
Considering the situation described, the values of the parameters are given as follows:
Hence the test statistic is:
t = -0.04
<h3>What is the p-value and the conclusion?</h3>Using a t-distribution calculator, for a left-tailed test, as we are testing if the mean is less than a value, with 10 - 1 = 9 df and t = -0.04, the p-value is of 0.4844.
Since the p-value is greater than 0.01, there is no evidence that the new machine should be rejected at the 0.01 significance level.
More can be learned about the t-distribution at brainly.com/question/13873630
#SPJ1
Answer:
The correct answer is 0.5 pounds of pollutant.
Step-by-step explanation:
According to the problem the cost of controlling emissions at a firm is given by:
C(q) = 1,260 + 100 × , where q is the reduction in emissions (in pounds of pollution per day) and C is the daily cost to the firm (in dollars) of this reduction.
Government clean-air subsidies amount to $100 per pound of pollutant removed per day.
Net cost = C(q) - Subsidy
⇒ Net Cost = 1,260 + 100 × - 100 × q.
In order to minimize net cost we calculate, (Net cost) = 0.
⇒ 200 × q - 100 = 0
⇒ q = 0.5
We can see that the second order derivative is positive and thus the net cost minimizes.
Thus the firm should remove 0.5 pounds of pollutant each day in order to minimize net cost.