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3 years ago

What is the solution of the system? Use the elimination method.

Mathematics

1 answer:

Yuki888 [10]3 years ago

7 0

I got D.There is no solution

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I really need help!!!

Zigmanuir [339]

Answer:

$Pr = 6.67\%$

Step-by-step explanation:

Given

$n = 10$ i.e. 10 people

Required

Probability of being next to each other

First, we calculate the total possible arrangements (without any restriction)

$Total = n!$

$Total = 10!$

If the three are to be next to each other,

First, we arrange the three

$r_1 = 3!$

Now, the 3 will be seen as 1; so, we have a total of 8 people i.e. (1 + 7 others)

The arrangement is:

$r_2 =8!$

So, the total arrangement, when they have to be next to one another is:

$r = r_1 * r_2$

$r = 3! * 8!$

The probability is:

$Pr = \frac{r}{n}$

$Pr = \frac{3! * 8!}{10!}$

Expand

$Pr = \frac{3*2*1 * 8!}{10*9*8!}$

$Pr = \frac{3*2*1}{10*9}$

$Pr = \frac{6}{90}$

$Pr = 0.0667$

Express as percentage

$Pr = 0.0667 * 100\%$

$Pr = 6.67\%$

8 0

3 years ago

76 m =<br> cm?????? Pls help I cant figure it out!!!

soldier1979 [14.2K]

Answer:

7600

Step-by-step explanation:

Because it is just x 100

8 0

3 years ago

60 is 15% of what number?

Norma-Jean [14]

Method 1

$\begin{array}{ccc}60&-&15\%\\x&-&100\%\end{array}\ \ \ \ |cross\ multiply\\\\15x=60\cdot100\\15x=6000\ \ \ \ \ |divide\ both\ sides\ by\ 15\\\boxed{x=400}$

Method 2

$\begin{array}{cccc}15\%&-&60&|divide\ both\ sides\ by\ 3\\\\5\%&-&20&|multiply\ both\ sides\ by\ 20\\\\100\%&-&400\end{array}$

Method 3

$p\%=\dfrac{p}{100}\\\\15\%=\dfrac{15}{100}=0.15\\\\0.15x=60\ \ \ \ |divide\ both\ sides\ by\ 0.15\\x=400$

7 0

3 years ago

Please help I don’t understand this

morpeh [17]

For the first one yes because you add essentially 1, but three times so you have 3x's whish is 3x. for problem two you get 8xy because of the common base number. number two is no. for number three. no,because you distribute the negative which woukd make negative x minus 8. number problem 4 yes because distrubute the 4 to the x and 5

6 0

3 years ago

Can someone help me?

horsena [70]

The answer is 16. ....

7 0

3 years ago