If you have line on the scatter plot that is drawn through the points (1,3) and (9,11) then we will first calculate the slope:
m=(y2-y1)/(x2-x1)=(11-3)/(9-1) = 8/8 = 1
Then the interception with y-axis:
y=mx+b
3= 1*1 + b
3-1=b
b=2
The equation is:
y=x+2
Answer:
B. 1x-3
Step-by-step explanation:
slope is m = 1
y-int = (0, -3)
2. Create frequency tables to represent the morning and afternoon dogs as two sets of data. Group the weights into classes that range 10 pounds. (4 points: 2 points for appropriate intervals, 2 points for correctly portraying data)
Morning
Range
Dogs
10 to 19
3
20 to 29
4
30 to 39
3
Afternoon
Range
Dogs
0 to 9
2
10 to 19
3
20 to 29
1
30 to 39
2
40 to 49
1
50 to 59
1
3. What is the median of the morning (AM) group? What is the median of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 25.5
Afternoon (PM): 19
4. What is the first quartile (Q1) of the morning (AM) group? What is the first quartile (Q1) of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 10
Afternoon (PM): 0
5. What is the third quartile (Q3) of the morning (AM) group? What is the third quartile (Q3) of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 20
Afternoon (PM): 10
6. What is the interquartile range (IQR) of the morning (AM) group? What is the interquartile range (IQR) of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 39
Afternoon (PM): 29
7. The average weights of the dogs are the same for the morning and afternoon groups. But based on your comparative box plot and the IQRs of the two groups, which group of dogs does you think would be easier to walk as one group? Why? (2 points: 1 point for the answer, 1 point for justification)
The morning dogs, there are fewer dogs and they seem to weigh less.
All of the answers I have here!
l need to get an answer for these questions
