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Inessa05 [86]
3 years ago
10

What 2 consecutive even integers have a sum of 217?

Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0

Let the 1st number be "2x"
The next consecutive even number is "2x+2"
EQUATION:
2x+2x+2=217
4x+2=217
4x=215
x is not an integer.
WHY?
The sum of two even integers must be even; it cannot be 217.
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14 is 20% of what number
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x* \frac{20}{100} =14:

x* \frac{2}{10} =14:

\frac{2x}{10} =14:

2x=14*10:

2x=140:

x=70

--

- - Good Homework - -


5 0
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Thickness of the book is ~

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2 years ago
Parallelogram ABCD is translated (x + 3, y − 2) and then rotated 90° about the origin in the clockwise direction. Complete the t
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Answer: A″ (−1, 2), B″ (1, 1), C″ (1, −1), D″ (−1, −2)

Step-by-step explanation:

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after translation, the corresponding points will be:

A (− 5, 1)   --> a(-5+3,1-2) = (-2,-1)

B (−4, 3)  --> b(-4+3,3-2) = (-1,1)

C (−2, 3)  --> c(-2+3,3-2) = (1,1)

D (−1, 1)    --> d(-1+3,1-2)  = (2,-1)

  • now the second part:

let (x,y) be a point and if it is rotated by "\alpha"

then, the new coordinates (x',y') will be :

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here, \alpha = 90 degrees

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a(-2,-1)  --> A"(-2cos[90]-1sin[90], -[-2]sin[90]+[-1]cos[90]) =(0-1, 2+0)=(-1,2)

(since, cos[90]=0, sin[90]=1)

b(-1,1)    -->B"(-1cos[90]+1sin[90], -[-1]sin[90]+1cos[90])=(1,1)

c(1,1)     --> C"(1cos[90]+1sin[90],-[1]sin[90]+1cos[90]) = (1,-1)

d(2,-1)   --> D"(2cos[90]+[-1]sin[90],-2sin[90]+[-1]cos[90]) =(-1,-2)

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7 0
4 years ago
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Step-by-step explanation:

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