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4 years ago

What is the volume of a right circular cylinder with a base diameter of 6 m and a height of 5 m?

2 answers:

6 0

If the diameter of it is 6, then its radius is half that.

$\bf \textit{volume of a right circular cylinder}\\\\
V=\pi r^2 h~~
\begin{cases}
r=radius\\
h=height\\
-----\\
r=3\\
h=5
\end{cases}\implies V=(\pi )(3^2)(5)$

madreJ [45]4 years ago

4 0

Volume of a cylinder: $\pi r^{2} h$

Plug in the numbers.

$\pi 3^25$ = 141.4

The volume of the cylinder is 141.4 m³.

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The inverse of the matrix $\left[\begin{array}{cc}11&-5\\3&-1\end{array}\right]$ is the matrix $\left[\begin{array}{cc}\frac{-1}{4} &\frac{5}{4} \\\\\frac{-3}{4} &\frac{11}{4} \end{array}\right]$ .

The inverse of a matrix A is calculated by the formula:

A' = (1/|A|)(Adj A),

where A' represents the inverse of matrix A,

|A| represents the determinant value of matrix A, and

Adj A represents the Adjoin matrix of matrix A.

So, to calculate the inverse of the matrix $\left[\begin{array}{cc}11&-5\\3&-1\end{array}\right]$ , we will first calculate its Adj.

Adj = $\left[\begin{array}{cc}-1&-3\\5&11\end{array}\right] ^{T}$ = $\left[\begin{array}{cc}-1&5\\-3&11\end{array}\right]$ .

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Therefore A' = (1/|A|)(Adj A),

or, A' = $(1/4)*\left[\begin{array}{cc}-1&5\\-3&11\end{array}\right]$ ,

or, A' = $\left[\begin{array}{cc}\frac{-1}{4} &\frac{5}{4} \\\\\frac{-3}{4} &\frac{11}{4} \end{array}\right]$ .

Therefore, the inverse of the matrix $\left[\begin{array}{cc}11&-5\\3&-1\end{array}\right]$ is the matrix $\left[\begin{array}{cc}\frac{-1}{4} &\frac{5}{4} \\\\\frac{-3}{4} &\frac{11}{4} \end{array}\right]$ .

Learn more about the inverse of a matrix at

brainly.com/question/16862241

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