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lana [24]
4 years ago
10

What are the foci of the hyperbola with equation 9y^2 - 16x^2 = 144?

Mathematics
1 answer:
Blizzard [7]4 years ago
7 0
I think the answer is

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Finds the value of x
arsen [322]

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2 x or 3x

Step-by-step explanation:

because is have x

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3 years ago
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a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera
seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

<u>Now, According to question</u>

The subscriber of newspaper after n years = initial subscriber × (1-\dfrac{\textrm rate}{100})^{\textrm time}

Or, P = p × (1-\dfrac{\textrm r}{100})^{\textrm t}

Or, 8200 = 10225 × (1-\dfrac{\textrm r}{100})^{\textrm 6}

Or, \dfrac{8200}{10225} =  (1-\dfrac{\textrm r}{100})^{\textrm 6}

Or, 0.80195 =  (1-\dfrac{\textrm r}{100})^{\textrm 6}

<u>Taking power \dfrac{1}{6} both side</u>

So, (0.80195 )^{\frac{1}{6}} = ((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}

Or, 0.9638 = 1 - \dfrac{r}{100}

Or,  \dfrac{r}{100} = 1 - 0.9638

Or,  \dfrac{r}{100} = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0
3 years ago
Our friend climbs 15 ft up a tree. They throw your headphones at you, and they go just over your head that is 5 feet tall
ioda

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5 ft away

Step-by-step explanation:

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3 years ago
Write the expression 5x+4x^2(2x+7)-6x^2-9x as a polynomial in standard form
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5x + 4x²(2x + 7) - 6x² - 9x
5x + 8x³ + 28x² - 6x² - 9x

8x³ + 22x² - 4x

This can be simplified to:

2x(4x² + 11x - 2)

I don't know which of those answers you are looking for. 
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4 years ago
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Dirt grows vegetables on a circular patch of land the radius of the patches 60 m what is approximately the area of the patch of
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meters or miles

Step-by-step explanation:

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