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Sonbull [250]
2 years ago
14

Round the number 196 to the nearest ten

Mathematics
1 answer:
yanalaym [24]2 years ago
7 0
Answer: 200

Explanation/Calculation: 6 (in the one's place) rounds to 10. So it would round up to ten. Therefore, the answer is 200.
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Which expression can be used to find the surface area of the following triangular prism?
vichka [17]

(B) but if there is another answers let me see cuz all i see is a and b

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On their first day of vacation, a family spent $127.92 for meals. The family spent $160.01 for meals the second day. By what amo
ehidna [41]

Answer:

D=32.09

Step-by-step explanation:

160.01-127.92=32.09

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Ab - bc+ ac, bc - ca+ ab, ca - ab-2bc
BabaBlast [244]

Answer:

ab-2bc+ca

Step-by-step explanation:

Complete question is given below

Add:-

ab-bc+ac,bc-ca+ab,ca-ab-2bc

We have to find the result after addition

Now, adding all expression

We get

ab-bc+ac+bc-ca+ab+ca-ab-2bc

Combine like terms then, we get

(ab+ab-ab)+(bc-bc-2bc)+(ac-ca+ca)

ab-2bc+ca

Hence,ab-bc+ac+bc-ca+ab+ca-ab-2bc=ab-2bc+ca

3 0
3 years ago
The frequency distributions of two data sets are shown in the dot plots below.
fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

\text{Mean of data set 1}=\frac{45}{19}

\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

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3 years ago
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Geoffrey is evaluating the expression (-3)^6(2^6)/(-3)^5(2^2) as shown below.
Alekssandra [29.7K]

Answer:

48.

Step-by-step explanation:

First you multiply the number by itself as many times as the number of the exponent is. In this case you <u>multiply -3 to itself 6 times which makes -729</u>, <u>2 to the 6th power is 64</u>, <u>-3 to the 5th power is -243, and 2 to the 2nd power is 4.</u> Then you <u>multiply -729 by 64 which makes -46656</u> and <u>multiply -243 by 4 which makes -972</u>, and then <u>divide -972 from -46656</u> <em>which makes 48</em>.

3 0
2 years ago
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