All categories

4 years ago

Find the cotangent of the angle in standard position in which the terminal side passes through the point (6, 8).

Mathematics

1 answer:

krok68 [10]4 years ago

3 0

Cotangent = adjacent / opposite = x / y = 6/8 = 3/4

Answer 3/4

You might be interested in

If an initial amount A0 of money is invested at an interest rate i compounded times a year, the value of the investment after t

seropon [69]

Answer:

Following are the solution to the given point:

Step-by-step explanation:

Please find the comp[lete question in the attached file.

Given:

$\bold{ \lim_{n \to \ \infty} (1+ \frac{r}{n})^{nt} =e^{rt}}$

In point 1:

$\to y = (1+ \frac{r}{n})^{nt}$

In point 2:

$\to \ln (y)= nt \ln(1+ \frac{r}{n})$

In point 3:

Its key thing to understand, which would be that you consider the limit n to $\infty$ , in which r and t were constants!

$=lim_{n \to \ \infty} \ln (y) = lim_{n \to \ \infty} nt \ln(1+\frac{r}{n})\\\\= lim_{n \to \ \infty} \frac{\ln(1+\frac{r}{n})}{\frac{1}{nt}}\\\\= lim_{n \to \ \infty} \frac{\frac{-r}{\frac{n^2}{(1+\frac{r}{n})}}}{- \frac{1}{n^2t}}\\\\= lim_{n \to \ \infty} \frac{\frac{rn^2t}{n^2}}{(1+\frac{r}{n})}\\\\= lim_{n \to \ \infty} \frac{rt}{(1+\frac{r}{n})}\\\\= \frac{rt}{(1+\frac{r}{0})}\\\\=rt$

In point 4:

$\to \lim_{n \to \ \infty} = (1+\frac{r}{n})^{nt}$ and

$\to \lim_{n \to \ \infty} = A_0e^{rt}$

7 0

3 years ago

Solve the system 16. 2x=y= 0 3x – 2y = -3

Lelu [443]

Answer:

the answer is x is 3 and y is 6

4 0

3 years ago

What is the solution to Multiply (Y-1)(y+8)

Setler79 [48]

whats is y? I can't solve the problem without it

4 0

3 years ago

HELP ASAP: What is the measure of angle A in the triangle? Enter your answer in the box

kondaur [170]

Answer:

Step-by-step explanation:

The sum of all the angles in a triangle is always, always, 180 degrees.

Just add the angles, then solve for x.

(2x - 10) + (x + 30) + 70 = 180

3x + 20 + 70 = 180

3x + 90 = 180

3x = 90

x = 30

6 0

4 years ago

Read 2 more answers

How do i do these inverse trig

jok3333 [9.3K]

This is a right triangle
so
Cos x = 109 / 134 then x = cos⁻¹ (109/134) = 35.567°
sin y = 109 / 134 then y = sin⁻¹ (109/134) = 54.433°
and
the third side = √(134² - 109²) = 77.94

8 0

3 years ago

Read 2 more answers