Yes they do. In order to do this you must make the fraction 70/2 and 105/3. If you divided each one of those you get 35 for both which means it's a proportion.
80 square units
Divide the figure into 4 small triangles, 2 rectangles, and one big rectangle on the center.
Area of ONE small triangle:
1/2 • 2 • 2 = 2 square units
Multiply that by 4 because we have 4 small triangles: 2 • 4 = 8 square units
Area of ONE small rectangle:
2 • 6 = 12 square units
Multiply that by 2 bcos we have 2 of those rectangles: 12 • 2 = 24 square units
Area of the big rectangle on the center:
6 • 8 = 48 square units
ADD the area of the big rectangle, 4 small triangles, and 2 small rectangles:
48 + 24 + 8 = 80
FINAL ANSWER: 80 square units
BRAINLIEST WILL BE APPRECIATED IF I GOT THIS RIGHT (pls comment me back if my answer was correct)
Have a nice day -SpaceMarsh
Answer:
the answer is b
Step-by-step explanation: edge 2020
The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
Given that,
The function is (-x+3)/ (3x-2)
We have to find f(1) and f'(x).
Take the function expression
f(x)= (-x+3)/ (3x-2)
Taking x as 1 value
f(1)= (-1+3)/(3(1)-2)
f(1)=2/1
f(1)=1
Now, to get f'(x)
With regard to x, we must differentiate.
f(x) is in u/v
We know
u/v=(vu'-uv')/ v² (formula)
f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²
f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4
f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4
f'(x)=2-9/ (9x²- 12x+4)
f'(x)=-7/ (9x²- 12x+4)
Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
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Answer:
No
Step-by-step explanation:
For a proportional relationship :
y = kx
Where , k = constant of proportionality
Taking the first set of data:
x = 50 ; y = 10
10 = 50k
k = 10/ 50 = 1/5
Hence, the proportional equation or relation is :
y = 1/5x
Check if this is true for other data points on the data :
Taking the second data point :
x = 85 ; check if y will be 20
From :
y = 1/5x
y = 1/5*85
y = 85/5
y = 17
Since ;
y value from the equation isn't the same as that in the table, then the table does not show a proportional relationship.
