Answer:
x3squared-3x2squared-18x
Step-by-step explanation:
1 Expand by distributing terms.
({x}^{2}-6x)(x+3)(x
2
−6x)(x+3)
2 Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d)=ac+ad+bc+bd.
{x}^{3}+3{x}^{2}-6{x}^{2}-18xx
3
+3x
2
−6x
2
−18x
3 Collect like terms.
{x}^{3}+(3{x}^{2}-6{x}^{2})-18xx
3
+(3x
2
−6x
2
)−18x
4 Simplify.
{x}^{3}-3{x}^{2}-18xx
3
−3x
2
−18x
Answer:
μ = 1 The firm expects that one oil exploration will be successful.
v(x)= 0.9
Step-by-step explanation:
The first step is to define the random variable x as:
x: number of oil explorations being succesful
Then x can be take this values:
x = 0 , x =1 ... x =10
x is a binomially distributed random variable with parameters.
p = 0.1 and n=10
And the mean or the expected value of x is:
μ = E(x) = np
Then μ = 10*0.1 = 1
And the variance of x is:
V(x) = np(1-p)
V(x) = 10(0.1)(1-0.1)= 0.9
Answer:
Yes it is linear
Step-by-step explanation:
Because when you go to graph it, it is a straight line. Hope this helped.....
Answer:
-4
Step-by-step explanation:
mark branliest :))
